1) The equation is already balanced;
Left side: 1C, 2H and 1O
Right side: 1C, 1O, 2H
2) Starting substances: water and carbon
There are two starting substances also called reactants. H2O which is a compound and C which is an element.
3) Ending substance asked for: H2.
This is hydrogen gas.
Stoichiometry:
1 mol of C produces 1 mol of H2
12.01 g of C productes 2.016 grams of H2
Ratio: 2.016 g of H2 / 12.01 g of C = X g of H2 / 34 g of C =>
x = 34 g of C* 2.016 g of H2 / 12.01 g of C= 5.707 g of H2
... in neutralization reactions, for example:
NaOH + HCl = NaCl + H₂O
2KOH + H₂SO₄ = K₂SO₄ + 2H₂O
A) C2H6O1
To find the emperical formula, divide each mole value by the smallest
For carbon, 0.013/0.0065 = 2
For hydrogen, 0.038/0.0065= 6
For oxygen, 0.0065/0.0065= 1
Emperical formula = C2H6O1
Stability of atoms is determined by neutron:proton ratio. This n/p ratio is 1:1 for elements below atomic number 20. Hope this helps.
