A student pushes a 40-N block across the floor for a distance of 10 m.

How many capsules containing 75mg of Tamiflu could be produced from 155g of star anise.?

jeyben [28]

From the question you will find that:
one capsule of tamiflu is obtained from 2.6 g of star anise.
1 capsule = 2.6 g tamiflu
? capsules = 155 g tamiflu
by cross multiplication = $\frac{(1 x 155)}{2.6}$ = 59 capsules

7 0

3 years ago

In this reaction, _____.

ella [17]

Answer:

AB + CD ----> AC + BD

Explanation:

If you think this reaction:

AB + CD ----> AC + BD

(Reactants) (Products)

All the statements are true.

7 0

3 years ago

Nitrogen gas is more abundant in our atmosphere than oxygen! However, nitrogen needs to be converted into different forms to be

Pavlova-9 [17]

Explanation:

(A)role of nittogen fixing bacteria

=Nitrogen-fixing bacteria, microorganisms capable of transforming atmospheric nitrogen into fixed nitrogen (inorganic compounds usable by plants). More than 90 percent of all nitrogen fixation is effected by these organisms, which thus play an important role in the nitrogen cycle.

B)role of nitrifying bacteria

=Nitrifying bacteria convert the most reduced form of soil nitrogen, ammonia, into its most oxidized form, nitrate. In itself, this is important for soil ecosystem function, in controlling losses of soil nitrogen through leaching and denitrification of nitrate.

C)role of denitrifying bacteria

=Denitrifying bacteria converts nitrates back to nitrogen gas.

4 0

3 years ago

Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago

The table above shows the number of protons in an Adam of four different elements according to the periodic table which of these

Maurinko [17]

Answer:

The correct answer is X

Explanation:

First have some idea about : Valency , Metals and non- metals.

Valency : It is the combining capacity of elements . The elements combine to other elements to gain stability . They always try to complete their octet(8 electrons in the outermost shell)

For Example : Na has 11 electron

Its electronic configuration is : 2 ,8 ,1 (2+8+1 = 11)

First shell contain maximum = 2 electron

2nd shell = maximum 8 electron

3 shell = maximum 18 electron

When it remove 1 electron from outermost shell , it is left with 2 ,8 configuration. Now , its outer most shell has 8 electron . so it get stable and show +1 valency.

When the element looses electron , it get positive charge

When the element gain electron it get negative charge

Metals: those element which show +1 , +2 , +3 valency are considered as metals

Non- metals = Those metals which show the valency of -1 , -2 ,-3 are considered as Non- Metals.

Questions:

1. T = 7 proton

Electronic configuration = 2 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

2. Q=15

Its electronic configuration = 2 ,8 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

3.X = 12

Its electronic configuration = 2 ,8 , 2

It loses (+ve charge) 2 electron to achieve complete octet( 2 , 8) = + 2 valency

It is metal

4.Z = 17

Its electronic configuration = 2 ,8 , 7

It gains (-ve charge) 1 electron to achieve complete octet(7+1 = 8) = -1 valency

It is non- metal

There is only one metal = X

4 0

3 years ago