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3 years ago

Why is snow a better insulator than ice?

Chemistry

2 answers:

Alchen [17]3 years ago

6 0

Snow contains air packets inside it; air is a good heat insulator

Anika [276]3 years ago

3 0

Answer:

Snow is a better insulator than ice because snow contains air packets inside it and air is a good insulator of heat. Due to this, snow takes longer time to melt than the ice of the same mass.

Explanation:

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How many electrons does F^-1 have?

sdas [7]

Answer:

Florine has 9 atomic number so it has 9 electrons. So, add 1 to the number of electrons it has. 9 + 1 = 10. F-

Explanation:

5 0

3 years ago

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Choose isomer of hexanoic acid?

Firlakuza [10]

Answer:

THR ANSWER IS C) _ methylpropanoate

7 0

3 years ago

a zinc block with a mass of 230 g is given 1320 j of energy what is the change in temperature of the block

viva [34]

Answer:

Q=msΔT

rearranging in terms of temperature gives:

ΔT=Q/ms

=1320j/(230g×0.338(j/g°C))

=16.97967584°C

=> ΔT=17.0°C

6 0

4 years ago

What is the percentage by mass of oxygen in a formula unit of sodium hydrogen carbonate (NaHCO3)?

nadezda [96]

Percent by mass of an element can be calculated as

(Total mass of the element in the formula / formula weight ) * 100

Step 1 : Find formula weight of NaHCO₃

To find formula weight of NaHCO₃, we have to add atomic masses of the elements Na, H,C and O

Formula weight of NaHCO₃ = $Na+H+C+3 (O)$

Formula weight of NaHCO₃ = $22.99+1.01+12.01+3(16)$

Formula weight of NaHCO₃ is 84.01 g

Step 2 : Use percent by mass formula

Percent by mass of oxygen = (total mass of oxygen / formula weight) * 100

Percent by mass of oxygen = $\frac{3(16)}{84.01} * 100$

Percent by mass of oxygen = 57.14%

Answer : percentage by mass of oxygen in a formula unit of sodium hydrogen carbonate (NaHCO3) is 57.14%

8 0

3 years ago

Read 2 more answers

A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc

rodikova [14]

Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = $1 g/cm^3=1 g/mL$

$1 mL= 1 cm^3$

$m=d\times v=1.0 g/mL\times 100.0 = 100.0 g$

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

$D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL$

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = $n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol$

Moles of water = $n_2=\frac{100.0 g}{18g/mol}=5.556 mol$

Mole fraction of phosphoric acid = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}$

$\chi_1=0.01803$

Mole fraction of water = $\chi_2$

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}$

$\chi_2=0.9820$

$[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

Moles of phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

$=\frac{0.1020 mol}{0.113 L}=0.903 M$

$[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}$

Moles of phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

$=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg$

6 0

3 years ago