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Ne4ueva [31]
3 years ago
14

Researchers have found that mitochondria and chloroplasts in eukaryotic cells have their own DNA. This DNA is different from the

DNA in a eukaryotic cell's nucleus. Chloroplasts and mitochondria use their own DNA and ribosomes to make some organelle-specific proteins.
What statement is best supported by this information?

A.
Early eukaryotic cells engulfed prokaryotic cells, which later became mitochondria and chloroplasts.
B.
Mitochondria and chloroplasts could exist outside of modern cells.
C.
Modern cells could exist without mitochondria and chloroplasts.
D.
Early prokaryotic cells engulfed eukaryotic cells, which later became mitochondria and chloroplasts.
Biology
1 answer:
ikadub [295]3 years ago
8 0

Answer:

B. Early Eukaryotic cells engulfed mitochondria and chloroplasts

Explanation:

Mitochondria and Chloroplast are organelle that are found in cells of higher animals. Chloroplast are found almost exclusively in plants and mitochondria is found in animal cells. The function of these organelles are to produce energy to the cells, and by extension, the organism that they live in.  

Unique features of these organelles show that they have their own DNA and divide and multiply on their own. This strongly suggest that they were once free living prokaryotes and were engulfed by larger cells and a symbiotic relationship began.

As time progressed, these prokaryotes did not require all of their genetic information and this was removed from their system. They kept essential genes and regulatory bodies separate that they needed for their maintenance and function that they provide.  

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In a standard monohybrid cross between purple-flowered and white-flowered peas, what fraction of the purple-flowered peas in the
Advocard [28]

Answer:

1/3

Explanation:

<em>A standard monohybrid cross is a cross that follows the dominance/recessive pattern from Mendel's experiment.</em>

It means the purple flower color is dominant over the white flower color.

Assuming the allele for purple flower color is P and that of the white flower color is p, a standard monohybrid cross will involve a true breeding PP and pp.

PP   x   pp: Pp, Pp, Pp and Pp. All the F1 offspring will have purple flowers with Pp genotype.

At F2: Pp   x   Pp = PP, Pp, Pp, and pp.

3/4 or 75% of the F2 offspring have purple flower color out of which 1 is true breeding for the trait.

Hence the fraction of the purple flowered peas in the F2 that is expected to be true-breeding (PP) is 1 out of 3.

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