All categories

4 years ago

Draw the alkyne formed when 2,3-dichloropentane is treated with an excess of strong base such as sodium amide.

Chemistry

2 answers:

Xelga [282]4 years ago

8 0

Hi! Thank you for posting your question here at Brainly. I hope I would be able to help you with my answer.

When an alkyne such as 2,3-dichloropentane is treated with excess sodium amide, a two-step elimination reaction will happen. The reaction would then yield the final product in the form of 2-pentyne. Its structure is shown in the attached image.

BartSMP [9]4 years ago

4 0

Answer: We obtain the alkyne 2-pentyne through E2 reaction mechanism.

Explanation:

Alkyl halides are compounds that contain a carbon chain in which one or more hydrogen atoms have been replaced by a halogen atom (F, Cl, Br, I) and are characterized by having halogen atoms in adjacent carbons. In the dehydrohalogenation the alkyl halide is reacted with a strong base. As a result an alkyne is obtained.

In this case we use sodium amide to favor the type E2 reaction mechanism (type 2 elimination) and we obtain the following alkyne:

You might be interested in

What are the differences between proton, neutron, and electron

AysviL [449]

A proton is positive energy, a neutron is neutral, and an electron is negative charge. Protons and neutrons are in the nucleus of an atom and electrons are on the electron cloud.

6 0

3 years ago

Which of the following is an example of chemical weathering?

Nonamiya [84]

Answer:O B. Weak acid breaks down minerals by reacting with them.

Explanation:

Chemical weathering is the process whereby rain water which sometimes can be acidic ( As rain falls down it reacts with CO2 in the atmosphere and form acid rain), This reacts with the minerals contained in rocks, dissolves and degrades them further to form entire new minerals.

An example of a rock that is greatly affected by overexposure of acid rain is limestone containing calcite which easily degrades by acid rain.

Other processes whereby Chemical weathering can occur are through reaction with water and oxygen.

4 0

3 years ago

Anastasy [175]

Answer:

I think it's letter B

Explanation:

Hope it helps correct if I'm wrong

7 0

3 years ago

The solid anhydrous solid CoCl2 is blue in color. Because it readily absorbs water from the air, it is used as a humidity indica

MrRissso [65]

Answer:

$CoCl_{2}.(H_{2}O)_{6}$ is formed and it has three unpaired electrons.

Explanation:

Blue $CoCl_{2}$ reacts with water to produce pink colored $CoCl_{2}.(H_{2}O)_{6}$ complex.

In this complex, $Co^{2+}$ ion forms an octahedral complex with six $H_{2}O$ ligands.

As $H_{2}O$ is a weak field ligand therefore $Co^{2+}$ ion remains in low spin state.

Hence electronic configuration of $Co^{2+}$ ion in this octahedral geometry is $t_{2g}^{5}e_{g}^{2}$ with total three unpaired electrons.

6 0

3 years ago

The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5

Sladkaya [172]

<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>

4 0

4 years ago

Read 2 more answers