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viva [34]
3 years ago
12

Which of the following is necessary to increase the rate of a reaction? A. a decrease in the frequency of collisions B. an incre

ase in the frequency of collisions C. a decrease in the frequency of successful collisions D. an increase in the frequency of successful collisions
Chemistry
2 answers:
g100num [7]3 years ago
8 0

Answer:

dd

Explanation:

liraira [26]3 years ago
5 0

Rate of the reaction is the decrease in concentration of the reactant or increase in the concentration of products per unit time.

Factors like concentration (pressure) of the reactant, nature of reactant, catalyst, surface area of the reactant, affect the reaction rate. Greater the concentration of the reactant, higher will be the number of effective collisions between the reactant molecules per unit time. So, the rate of reaction would increase with increase in frequency of successful collisions due to the increase in concentration of the reactants.

So, the correct answer is D. an increase in the frequency of successful collisions

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Answer:

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Explanation:

How is hydrofluoric acid made?

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A large highway barrier is 1 meter wide, by 1 meter tall, by 2 meters long.
Romashka [77]

Answer:

when mass is  1×10⁴ Kg then density is 5 g/cm³.

when mass is 104 Kg then density is 5.2 × 10⁻² g/ cm³.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass = 1×10⁴ Kg

volume= w ×l× h = 1×2× 1 = 2 m³

density = ?

first of all we will convert the given volume meter cube to cm³:

we know that  

2×1000000 = 2 × 10⁶ cm³

Now we will convert the mass into gram.

1 Kg = 1000 g

1×10⁴ × 1000 = 1 ×10⁷ g

Now we will put the values in the formula,

d = m/v

d = 1 ×10⁷ g / 2×10⁶ cm³

d = 0.5 × 10¹ g/cm³

   or

d = 5 g/cm³

If mas is 104 Kg:

104 × 1000 = 104000 g

d= m/v

d = 104000 g / 2×10⁶ cm³

d= 52000 ×10⁻⁶ g/ cm³

d= 5.2 × 10⁻² g/ cm³

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Answer:

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