Which of the following is necessary to increase the rate of a reaction? A. a decrease in the frequency of collisions B. an incre
2 answers:
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<u>Explanation:</u>
pH is the negative logarithm of hydronium ion concentration present in a solution.
- If the solution has high hydrogen ion concentration, then the pH will be low and the solution will be acidic. The pH range of acidic solution is 0 to 6.9
- If the solution has low hydrogen ion concentration, then the pH will be high and the solution will be basic. The pH range of basic solution is 7.1 to 14
- The solution having pH equal to 7 is termed as neutral solution.
To calculate the pH of the solution, we use equation:
......(1)
To calculate the pOH of the solution, we use the equation:
pH + pOH = 14 ........(2)
- <u>For 1:</u>
We are given:
pH = 5.54
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 5.54 + pOH
pOH = 8.46
The solution is acidic in nature.
- <u>For 2:</u>
We are given:
pOH = 9.7
Putting values in equation 2, we get:
14 = 9.7 + pH
pH = 4.3
Now, putting values in equation 1, we get:
The solution is acidic in nature.
- <u>For 3:</u>
We are given:
pH = 7.0
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 7.0 + pOH
pOH = 7.0
The solution is neither acidic nor basic in nature.
- <u>For 4:</u>
We are given:
pH = 12.9
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 12.9 + pOH
pOH = 1.1
The solution is basic in nature.
- <u>For 5:</u>
We are given:
pOH = 1.2
Putting values in equation 2, we get:
14 = 1.2 + pH
pH = 12.8
Now, putting values in equation 1, we get:
The solution is basic in nature.
- <u>For 6:</u>
We are given:
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 5 + pOH
pOH = 9
The solution is acidic in nature.
Answer:
49.2 g/mol
Explanation:
Let's first take account of what we have and convert them into the correct units.
Volume= 236 mL x () = .236 L
Pressure= 740 mm Hg x ()= 0.97 atm
Temperature= 22C + 273= 295 K
mass= 0.443 g
Molar mass is in grams per mole, or MM= or MM=
. They're all the same.
We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be
n=, where R (constant)= 0.082 L atm mol-1 K-1
Let's plug in what we know.
n=
n= 0.009 mol
Let's look back at MM= and plug in what we know.
MM=
MM= 49.2 g/mol