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viva [34]
3 years ago
12

Which of the following is necessary to increase the rate of a reaction? A. a decrease in the frequency of collisions B. an incre

ase in the frequency of collisions C. a decrease in the frequency of successful collisions D. an increase in the frequency of successful collisions
Chemistry
2 answers:
g100num [7]3 years ago
8 0

Answer:

dd

Explanation:

liraira [26]3 years ago
5 0

Rate of the reaction is the decrease in concentration of the reactant or increase in the concentration of products per unit time.

Factors like concentration (pressure) of the reactant, nature of reactant, catalyst, surface area of the reactant, affect the reaction rate. Greater the concentration of the reactant, higher will be the number of effective collisions between the reactant molecules per unit time. So, the rate of reaction would increase with increase in frequency of successful collisions due to the increase in concentration of the reactants.

So, the correct answer is D. an increase in the frequency of successful collisions

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1) A book is pushed and released and it slides across a table for a short distance The book quickly comes to a stop. The book or
valina [46]

Answer: A the kinetic energy is transformed into heat

Explanation:

3 0
2 years ago
Which of the following is a reactant in aerobic respiration?
IrinaVladis [17]
The reactant in aerobic respiration is oxygen (answer C)
3 0
2 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
3 years ago
3k+aici3 3kci+ai is what type of reaction
exis [7]
3K      +     AlCl3 -------->  3 KCl     +          Al
element    compound     compound       element

This is single replacement (displacement) reaction.
3 0
3 years ago
Which is the best practice recommended in the safety video to mix and acid or a base with a solvent?
Vesna [10]

Answer:

Never pour water into acid but acid into water

Explanation:

If water is poured into extremely concentrated acid/bases, the rate of volatility and exothermic reaction is too rapid and might cause a chemical eruption, leading to acid burns.

Safety precautions hence dictate the reverse is practiced.

I believe this is a clear answer.

4 0
3 years ago
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