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viva [34]
3 years ago
12

Which of the following is necessary to increase the rate of a reaction? A. a decrease in the frequency of collisions B. an incre

ase in the frequency of collisions C. a decrease in the frequency of successful collisions D. an increase in the frequency of successful collisions
Chemistry
2 answers:
g100num [7]3 years ago
8 0

Answer:

dd

Explanation:

liraira [26]3 years ago
5 0

Rate of the reaction is the decrease in concentration of the reactant or increase in the concentration of products per unit time.

Factors like concentration (pressure) of the reactant, nature of reactant, catalyst, surface area of the reactant, affect the reaction rate. Greater the concentration of the reactant, higher will be the number of effective collisions between the reactant molecules per unit time. So, the rate of reaction would increase with increase in frequency of successful collisions due to the increase in concentration of the reactants.

So, the correct answer is D. an increase in the frequency of successful collisions

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You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
Please answer these about Charles law
NNADVOKAT [17]

Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

6 0
3 years ago
Skin cells _____.
Gekata [30.6K]

Hey, the two answers that would best fit in the blank would be B.) reproduce by mitosis & D.) Have 46 chromosome pairs.


Sentence form: Skin cells reproduce by mitosis and have 46 chromosome pairs.

5 0
3 years ago
Is it possible for two different compounds to be made from the exact same two elements? Why or why not? With a limited number of
daser333 [38]

Answer:

Yes. The two elements can combine to form different compounds.

Explanation:

Two elements can combine at different ratios.

Consider CO and CO₂. Both are made from carbon and oxygen. However, C and O combine at a 1:1 ratio in CO but at a 1:2 ratio in CO₂. CO is a fuel; it burns in the air. CO₂ does not burn in the air; it is used to put out fires and is found in extinguishers. CO and CO₂ are two distinct compounds.

There are many ways for the elements to combine with each other. As a result, the first twenty elements on the periodic table alone can produce a large number of compounds.

6 0
3 years ago
A sugar cube was placed into a beaker containing 100 mL of water at room temperature and completely dissolved into the water. Th
Bad White [126]

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

3 0
3 years ago
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