In an electrochemical cell in which the oxidation reaction is nonspontaneous the oxidation will not occur spontaneously at the anode and the reduction will not be spontaneous at the cathode. And according to the law for the calculation of the voltage potential of the electrochemical cell (Ecell):
Ecell = Eox. - Ere. where (Eox. is the potential of the oxidation at the anode and Ere. is the potential of the reduction at the cathode). The standard potential for an electrolytic cell is negative, because of the Ere. which is greater than Eox.
The answer is : less than zero.
Na(s) forms an ionic bond.
<h3>What is ionic bond?</h3>
The main interaction in ionic compounds is ionic bonding, a type of chemical bonding that involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities. Along with metallic and covalent bonds, it is one of the most common types of bonds. Atoms (or collections of atoms) possessing an electrical charge are known as ions. Ions with negative charges are created when atoms gain electrons (called anions). Positively charged ions are produced when atoms lose electrons (called cations). In contrast to covalence, this electron transfer is referred to as electrovalence.
Ionic chemicals normally do not conduct electricity when solid, only when molten or in solution. Depending on the charge of the ions they are made of, ionic compounds typically have a high melting point.
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Arenal Volcano: Plate Tectonic Setting. The volcanic arc of Costa Rica, where Arenal is located, is a chain of mountains resulting from the subduction of the Cocos tectonic plate under the Caribbean Plate. Costa Rica is part of the Central American isthmus, which connects the North and South American continents.
Answer:
moving i think! Hope this helps
Explanation:
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
</span><span>E = +1.47
</span>
<span>Br(l) + 2e- = 2Br-
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
