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3 years ago

Find all real numbers x such that 4x - 18 > 2 and-17x - 8 < -25

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

its actually the middle bar with the arrows going across the whole bar, for PLATO

Step-by-step explanation:

Rashid [163]3 years ago

7 0

The answer is on the bottom. Hope this helps.

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Someone plz answer this for me

padilas [110]

Cos theta = base /perp = sqrt(13)/7 =0.515

4 0

3 years ago

convert the mixed numbers to improper fractions. this will get you one step closer to finding the unit rate

Kaylis [27]

It means for example instead of writing 2 2/5 You would write 12/5
You can find out an improper fraction by simply multiplying the denominator by the front number and adding the answer to you numerator
So, 2x5= 10. 10+2= 12. So 12/5

8 0

3 years ago

What's the sum of 5 feet 9 inches in 12 ft and 3 in

galben [10]

First convert everything into inches.

1 foot = 12 in
5 feet = 5*12 = 60 in
12 feet = 12*12 = 144 in

Now add them together

60 + 9 + 144 + 3 = 216 in

or

18 feet

Hope this helps :)

4 0

3 years ago

If 9x = 63, then x = ___. (Only input whole number) Numerical Answers Expected! Answer for Blank 1:

lina2011 [118]

If 9x = 63, then x = 7

5 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago