Balance Chemical Equation of this reaction is,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
Answer:
you can see the answer at the pic
Mmm, you can work this one out in your head by reversing it.
<span>12.5 = 50g/4 </span>
<span>1/4 = 1/2 * 1/2 </span>
<span>thus in 14.4 seconds there have been 2 times the half life. 14.4/2 = 7.2 </span>
<span>the half life is 7.2 seconds.</span>
