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Veseljchak [2.6K]
3 years ago
6

Can we talk about planets or talk about life lol (keep kid friendly)

Chemistry
2 answers:
Andrew [12]3 years ago
8 0

Answer:

Yeah sure I will talk :)

frosja888 [35]3 years ago
5 0

Answer:

About planets or life

Explanation:

There we talked about planets and life Lol

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If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow abs
Arisa [49]

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

<h3>What is entropy? </h3>

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

<h3>Formula:</h3>

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

learn more about entropy:

brainly.com/question/14131507

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2 years ago
The process of joining many small molecules into larger molecules is called(1) neutralization (3) saponification(2) polymerizati
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(2) polymerization. polymerization<span> is a process of reacting monomer molecules together in a chemical reaction to form polymer chains or three-dimensional networks.</span>
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What do you call a circuit with only one path
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If I'm correct the answer should be a series circuit :) Hopefully this helps you out
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3 years ago
What is the energy of a radio wave whose frequency is 6.2 x 106 Hz?
slava [35]

Answer:

657.2 Hz

Explanation:

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3 years ago
The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the
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Answer: 0.225 atm

Explanation:

For this problem, we have to use Boyle's Law.

Boyle's Law: P₁V₁=P₂V₂

Since we are asked to find P₂, let's manipulate the equation.

P₂=(P₁V₁)/V₂

P_{2} =\frac{(1.00atm)(0.45L)}{2.00L}

With this equation, the liters cancel out and we will be left with atm.

P₂=0.225 atm

6 0
3 years ago
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