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Akimi4 [234]
3 years ago
12

Which is the FALSE statement about C-14?

Chemistry
2 answers:
slega [8]3 years ago
7 0

The answer is: A


C-14 is not stable and this is the reason why it goes through radioactive decay.

RSB [31]3 years ago
5 0

Answer : The false statement is, (A) It is a stable isotope.

Explanation:

Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.

Carbon has three isotopes which are carbon-12, carbon-13 and carbon-14.

Carbon-14 is an unstable isotope which is radioactive isotope and it is present in all the living things.

Carbon-14 is used to calculate the age of of remains.

Hence, the false statement is, (A) It is a stable isotope.

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4 years ago
The osmotic pressure of a saturated solution of strontium sulfate at 25 ∘C∘C is 21 torrtorr. Part A What is the solubility produ
USPshnik [31]

Answer

solubility product = 3.18x 10^-7

Explanation:

We were given the pressure in torr then we need to convert to atm for consistency, ten we have

21torr/760= 0.0276315789 atm

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M = P / iRT

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for XY vanthoff factor i = 2

S = 0.0821 L-atm / mol K

M = .0276315789 atm / (2)(0.0821 L atm / K mole)(298 K)

M = 0.000564698046 mol/liters

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Ksp = [X+][Y-]

Ksp = X^2

Ksp = [Sr^+2] * [SO4^-2]

Ksp = X^2

Ksp = (0.000564698046)^2

Ksp = 3.18883883 × 10-7

Ksp = 3.18x 10^-7

solubility product = 3.18x 10^-7

Therefore, the solubility product of this salt at 25 ∘C∘C is 3.18x 10^-7

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During a phase change
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