Answer:
0.295 L
Explanation:
It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:
" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "
Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.
To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂
Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.
- 47.2 mL * 150 mM = 24.0 mM * V₂
And <u>converting into L </u>becomes:
- 295 mL *
= 0.295 L
Answer:
Arrow should be yeilds, THE COEFFICIENTS are mole ratios. So every 4 moles of NH3 or ammonia produce 6 moles of H2O water
Yogurt, kefir, kombucha, sauerkraut, pickles, miso, tempeh, kimchi, sourdough bread and some cheeses.
Ionic compounds conduct electricity when dissolved in water, because the free-floating ions can carry charge. The more ions you have, the more readily the solution will carry that charge. 10.0 mL of 0.10 M NH4Cl has only 0.001 mol of NH4+ and 0.001 mol of Cl-, whereas 10.0 mL of 0.30 NH4Cl has 0.003 mol of NH4+ and 0.003 mol of Cl-. The 0.10 M sample is a poorer conducted of electricity because it has less ions in solution.
Answer:
<u>The new pressure is 1.0533 atm</u>
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Explanation:
According to<u> Boyle's Law :</u> The Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.
PV = Constant
P1V1 = P2V2
.....(1)
P1 = 3.16 atm
Accprding to question ,
V1 = V
V2 = 3 V
Insert the value of V1 , V2 and P1 in the equation(1)
V and V cancel each other
