Ah yes, my school next year! Imma be in HIGH SCHOOLLLLLLLLLLLLL! YAY!

Is sugar (C12H22O11) an element or a compound?

Semmy [17]

I believe that sugar is a compound because there are elements that make up sugar

4 0

3 years ago

Is sulfur a metal, nonmetal, metalloid, or noble gas?

Blababa [14]

Sulfer is a nonmetal

6 0

1 year ago

It is primarily used as energy storage found in the cell membrane

Gnesinka [82]

Answer:

ATP—Adenosine triphosphate, a nucleotide which is the most important short-term energy storage compound in cells. It is the “energy currency” of the cell, necessary for practically all metabolic activities. Carbohydrate—A type of organic molecule made of carbon, hydrogen, and oxygen.

4 0

2 years ago

Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli

SashulF [63]

88.98 %

The Balance Chemical Equation is as follow,

2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂

According to equation,

331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂

So,

870 g of Pb(NO₃)₂ will produce = X g of PbCl₂

Solving for X,

X = (870 g × 278.1 g) ÷ 331.2 g

X = 730.5 g of PbCl₂

Therefore,

Theoretical Yield = 730.5 g

Also as given,

Actual Yield = 650 g

So using following formula for percentage yield,

%age Yield = (Actual Yield / Theoretical Yield) × 100

Putting values,

%age Yield = (650 g / 730.5 g) × 100

%age Yield = 88.98 %

Brianliest please and thank you.

4 0

3 years ago

When 25.0 g of ch4 reacts completely with excess chlorine yielding 45.0 g of ch3cl, what is the percentage yield, according to c

Ber [7]

Taking into account definition of percent yield, the percent yield for the reaction is 57.08%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + Cl₂ → CH₃Cl + HCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole
Cl₂: 1 mole
CH₃Cl: 1 mole
HCl: 1 mole

The molar mass of the compounds is:

CH₄: 16 g/mole
Cl₂: 70.9 g/mole
CH₃Cl: 50.45 g/mole
HCl: 36.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole ×16 g/mole= 16 grams
Cl₂: 1 mole ×70.9 g/mole= 70.9 grams
CH₃Cl: 1 mole ×50.45 g/mole= 50.45 grams
HCl: 1 mole ×36.45 g/mole= 36.45 grams

Mass of CH₃Cl formed

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 50.45 grams of CH₃Cl, 25 grams of CH₄ form how much mass of CH₃Cl?

$mass of CH_{3} Cl=\frac{25 grams of CH_{4}x 50.45grams of CH₃Cl }{16 grams of CH_{4}}$

<u><em>mass of CH₃Cl= 78.83 grams</em></u>

Then, 78.83 grams of CH₃Cl can be produced from 25 grams of CH₄.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

$percent yield=\frac{actual yield}{theorical yield}x100$

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know: