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LiRa [457]
3 years ago
14

As a Ca atom undergoes oxidation to Ca2+, the number of neutrons in its nucleus

Chemistry
2 answers:
maria [59]3 years ago
6 0
Oxidation refers to a change in electrons (In this case, loss of electrons). It has no impact on the number of neutrons, or for that matter on any sub-atomic particles in the nucleus. So the number of neutrons (3) remains the same
Lemur [1.5K]3 years ago
3 0

Answer:

Hence the correct answer is remains the same

Explanation:

As a Ca atom undergoes oxidation to Ca2+,as follows:

Ca --- Ca 2+ + 2e-

In the process of oxidation calcium loss 2 electron only there is no change in the number of protons as well neutrons therefore there is no change in the number of neutrons in its nucleus

Hence the correct answer is remains the same

Oxidation:

Oxidation is a process in which either 1 or all following changes occurs:

1. Gaining of oxygen atoms

2. Loss of electrons

3. Loss of hydrogen atom.

4. Increasing oxidation number.

Reduction:

Reduction is a process in which either 1 or all following changes occurs:

1. Loss of oxygen atoms

2. Gaining of electrons

3. Gaining of hydrogen atom.

4. Decreasing oxidation number.

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Where are chemicals found in our home
alexandr402 [8]

Answer:

Cleaning products like bleach, oven sprays, liquid laundry capsules and toilet cleaners are chemicals. So are paints, glues, oils, pesticides and medicines. Most of the chemicals you use at home aren't dangerous if you use them properly. However, some chemicals need more careful handling than others.

8 0
3 years ago
Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with
mestny [16]

Answer:

The weight of ammonium phosphate is 10 gm

Explanation:

The chemical reaction of ammonium phosphate formation is as follows.

3NH_{3}+H_{3}PO_{4} \rightarrow [(NH_{4})_{3}PO_{4}]

From the reaction one mole of phosphoric acid is equivalent to the one mole of ammonium phosphate.

So, "n" mole of phosphoric acid is equivalent to the "n" mole of ammonium phosphate.

Number of moles in 7.1 grams of phosphoric acid = \frac{7.1}{Molarmass\,of phosphoric\,acid}

\frac{7.1}{98}= \frac{1}{13.8}

<u>Formation weight of ammonium phosphate :</u>

Weight of ammonium phosphate = = \frac{1}{13.8}\times Molarmass\,of\,\,ammonium\,phosphate

=\frac{149}{13.8} = 10.79gm

Round the answer to 2 significant digits

Weight of ammonium phosphate = 10 gm

7 0
3 years ago
Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq)→ Cu3(PO4)2(s)+6NaCl(aq)
Troyanec [42]

Answer:

V= 37.0 mL

Explanation:

First find the moles of the known substance (CuCl2)

n= cv

where

n is moles

c is concentration

v is volume ( in litres)

n= 0.108 × 0.0946

n=0.0102168

Using the mole ratio in the balanced reaction, we can find the moles of Na3PO4

n (Na3PO4)= n (CuCl2) × 2/3

=0.0102168 × 2/3

=0.0068112

Now we have all the necessary values to calculate the volume

v=n/c

v= 0.0068112/0.184

v= 0.0370173913 L

v= 37.0 mL

6 0
4 years ago
Calculate the density of nitrogen gas, in grams per liter, at stp.
lesantik [10]

Standard temperature is 273 K

Standard pressure is 1 atm

We use the ideal gas equation to find out density of nitrogen gas in g/L

Ideal gas equation:

PV = nRT\\  PV = (\frac{Mass}{Molar mass)}RT\\   P(Molar mass) = (\frac{Mass}{Volume})RT\\  \frac{Mass}{Volume}=\frac{P(molar mass)}{RT} \\  Density = \frac{P(Molar mass)}{RT}

Molar mass of N_{2} = 28 g/mol

Pressure = 1 atm

Temperature = 273 K

Density = \frac{(1atm)(28 g/mol)}{(0.08206 \frac{L.atm}{mol.K})(273 K)}

= 1.25 g/L

Therefore, density of nitrogen gas at STP is 1.25 g/L

4 0
3 years ago
What is the wavelength of an x-ray that has a frequency 7.8×10^17
Virty [35]

Answer:

λ = 0.38 ×10⁻⁹ m

Explanation:

Wavelength of xray = ?

Frequency of xray = 7.8 ×10¹⁷ Hz

Solution:

Formula:

Speed of light = wavelength × frequency

speed of light = 3×10⁸ m/s

Now we will put the values in formula.

3×10⁸ m/s = λ × 7.8 ×10¹⁷ Hz

λ = 3×10⁸ m/s / 7.8 ×10¹⁷ Hz

        Hz = s⁻¹

λ = 3×10⁸ m/s / 7.8 ×10¹⁷s⁻¹

λ = 0.38 ×10⁻⁹ m

8 0
3 years ago
Read 2 more answers
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