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2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: ,

1 answer:

6 0

Bynari means that the compound is formed by two kind of elements.

You have listed three ions, V 5+, Cl - and O 2-.

Binary ionic compounds are formed by a positive ion and a negative ion, so the possible ionic compound formed by the listed ions are:

1) VCl5, where the number 5 next to Cl is a subscript.

2) V2O5, where the number 2 next to V and the number 5 next to O are subscripts.

Subscripts are used to indicate the number of atoms of each element in the formula.

So, the empirical formula searched are VCl5 and V2O5.

I can give you other examples with more ions.

Ca (2+) and S(2-) => Ca2S2 => CaS

Na(+) and F(-) => NaF

Cs(+) and Br(-) => CsBr

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The pressure of 6.00 L of gas increases from 1.50 atm to 2.00 atm. What is the final volume of the gas, assuming constant temper

xeze [42]

Answer:

first we need to convert everything in SI units

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2 years ago

A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A

Kryger [21]

Answer:

$T_{2}=16,97^{\circ}C$

Explanation:

The specific heats of water and steel are

$Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}$

$Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}$

Assuming that the water and steel are into an adiabatic calorimeter (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium $T_{2}_{w}= T_{2}_{s}$

An energy balance can be written as

$m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}$

Replacing

$1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)$

Then, the temperature $T_{2}=16,97^{\circ}C$

8 0

2 years ago

1 Point

AleksandrR [38]

Answer:

Explanation:

A or B

I would say B do

4 0

2 years ago

A solution of potassium hydroxide reacts completely with a solution of nitric acid. What solid mixture does it create?

KIM [24]

Answer:

$\boxed{\text{KNO}_{3}}$

Explanation:

The reaction is

KOH(aq) + HNO₃(aq) ⟶ KNO₃(aq) + H₂O(ℓ)

If you evaporate the water, the solid substance is the compound, potassium nitrate.

$\boxed{\textbf{KNO}_{3}}$

KNO₃(aq) ⟶ KNO₃(s)

4 0

2 years ago

2. ATO kg bouting ball would require what force to accelerate down an alleyway at a rate of ons?

Mars2501 [29]

Answer:

2. 30N

3. 5,000N

4. 15 kg

5. 2,800 kg

Explanation:

2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?

Notice that I completed the question with the garbled and missing values:

Data:

F = ?

m = 10 kg

a = 3m/s²

Physical principles:

Newton's second law: $F=m\times a$

Solution:

Substitute and compute

$F=10kg\times 3m/s^2=30N$

3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?

Notice that I arranged the typos.

Data:

F = ?

m = ?

a = ?

Physical principles:

Newton's second law: $F=m\times a$

Solution:

Substitute and compute

$F=1,000kg\times5m/s^2=5,000N$

4. What is the mass of a falling rock if it produces a force of 147 N?

Data:

F = 147N

m = ?

a = falling rock

Physical principles:

neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²

Newton's second law: $F=m\times a$

Solution:

Clear m from Newton's second law

$m=\dfrac{F}{a}$

Substitute with F = 147 N and a = g = 9.8m/s², and compute

$m=\dfrac{147N}{9.8m/s^2}=15Kg$

5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?

Data:

F= 14,000N

m = ?

a = 5m/s²

Physical principles:

Second Newton's law: $F=m\times a$

Solution:

Clear m from Newton's second law

$m=\dfrac{F}{a}$

Substitute with F = 14,000 N and a = 5m/s², and compute

$m=\dfrac{14,000N}{5m/s^2}=2,800kg$

6 0

2 years ago