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kondor19780726 [428]
3 years ago
12

Light-rail passenger trains that provide transportation within and between cities are capable of modest accelerations. The magni

tude of the maximum acceleration is typically 1.3 m/s2 , but the driver will usually maintain a constant acceleration that is less than the maximum. A train travels through a congested part of town at 4.0m/s . Once free of this area, it speeds up to 13m/s in 8.0 s . At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.
What is the final speed?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Mkey [24]3 years ago
3 0
During the first phase of acceleration we have:
v o = 4 m/s;  t = 8 s; v = 13 m/s, a = ?
v = v o + a * t
13 m/s = 4 m / s + a * 8 s
a * 8 s = 9 m/s
a = 9 m/s : 8 s
a = 1.125 m/s²
The final speed:
v = ?;  v o = 13 m/s; a = 1.125 m/s² ;  t = 16 s
v = v o + a * t
v = 13 m/s + 1.125 m/s² * 16 s
v = 13 m/s + 18 m/s = 31 m/s 
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olya-2409 [2.1K]

Atoms consist of protons, neutrons and electrons

Explanation:

There are three particles in an atom:

  • Proton: it is located in the nucleus. Its mass is m_p = 1.6726\cdot 10^{-27}kg, and it is positively charged (its electric charge is +1.6\cdot 10^{-19}C, also  called fundamental charge)
  • Neutron: it is also located in the nucleus. Its mass is slightly larger than the proton (m_n = 1.6749\cdot 10^{-27}kg), and it has no electric charge. Protons and neutrons are held together inside the nucleus by the strong nuclear interaction
  • Electron: it is located outside the nucleus, in a region called "electron cloud". According to quantum mechanics, its exact position cannot be determined, but it can only be described by a "wave function" which gives the probability of finding the electron at a certain position. Its mass is much smaller than the proton (m_e = 9.11\cdot 10^{-31} kg) and it is negatively charged (its charge is the opposite of that of the proton: -1.6\cdot 10^{-19}C).

Learn more about atoms:

brainly.com/question/2757829

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3 0
3 years ago
Two objects attract each other gravitationally with a force of 2.5 x 10^-10N when they are 0.25 m apart. Their total mass is 4.0
In-s [12.5K]

Answer:

M = 3.9406 kg and m = 0.0594 kg

Explanation:

The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically it is expressed as follows:

Fg = (G×M×m)/r²    Formula (1)

Where:

Fg is the gravitational force (N)

G is the universal gravitation constant, G = 6.67 × 10⁻¹¹ (N×m²)/kg²

M and m are the masses of the bodies that interact  (kg).

r is the distance that separates them (m).

Known Data

Fg = 2.5 × 10⁻¹⁰ N

r = 0.25 m

G = 6.67 × 10⁻¹¹ (N×m²)/kg²

Problem development

We propose 2 equations

M + m = 4kg

M = 4 - m equation (1)

We replace in formula (1)

2.5 × 10⁻¹⁰ = (6.67 × 10⁻¹¹ × M × m)/(0.25)²

2.5 × 10⁻¹⁰ × (0.25)² = (6.67 × 10⁻¹¹ × M × m)

(2.5 × 10⁻¹⁰ × (0.25)²)/(6.67 × 10⁻¹¹) = M × m

M × m = 0.234 equation (2)

We replace M = 4 - m in equation (2)

(4 - m) × m = 0.234

4m - m² = 0.234

m² - 4m + 0.234 = 0 (quadratic equation)

We apply the formula for the quadratic equation and obtain 2 values for m that meet the conditions:

m = 3.9406 kg or m =  0.0594 kg

We replace m in equation (1)

M = 4 - 3.9406 = 0.0594 kg or M = 4 - 0.0594 = 3.9406

To meet the condition that M + m must give 4 kg, one mass must be equal 3.9406 and the other must equal 0.0594, then:

M = 3.9406 kg and m = 0.0594 kg

6 0
4 years ago
an object of mass 1 g is hung from a spring and set in oscillatory motion .At t=0 the displacement is 43.75cm and the accelerati
charle [14.2K]

The spring constant is 4.0\cdot 10^{-5} N/m

Explanation:

For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

a=-\omega^2 x

where

a is the acceleration

\omega is the angular frequency

x is the displacement

The angular frequency is defined as

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Substituting the second equation into the first one, we get

a=-\frac{k}{m}x

In this problem we have

m = 1 g = 0.001 kg

And at t=0,

x = 43.75 cm

a = -1.754 cm/s

Therefore, we can re-arrange the equation above to find the spring constant:

k=-\frac{ma}{x}=-\frac{(0.001)(-1.754)}{43.75}=4.0\cdot 10^{-5} N/m

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6 0
3 years ago
A ball is thrown down vertically with an initial speed of 31 ft/s from a height of 40 ft. (a) What is its speed just before it s
ICE Princess25 [194]

Answer:

a. 41.96ft/s

b. 1.096s

Explanation:

a. v²=u²+2gs

v²=31²+2×10×40

V=41.96ft/s

b. t=(v-u) /g

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5 0
3 years ago
How do you think the body deals with consuming a lot more<br> calories than are burnt?
natali 33 [55]

Answer:

The body stores it as fat

Explanation:

3 0
3 years ago
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