Answer:
b. The normal force between the molecules of the paper is overcome by the contact force of the hands.
Explanation:
The paper molecules are held together by a weak bond. When the student holds the paper on both sides with the center of the paper in between, the student applies two equal forces in the opposite direction of the paper making the paper molecules weaken and separate.
Kinetic energy is the energy associated with the motion of an object. It's a scalar quantity, there is no direction associated with KE and it has no components.
![KE = \frac{mv ^{2} }{2} = \frac{8 *14.3 ^{2} }{2} = 4 *204.49 = 817.96J](https://tex.z-dn.net/?f=KE%20%3D%20%20%5Cfrac%7Bmv%20%5E%7B2%7D%20%7D%7B2%7D%20%3D%20%20%5Cfrac%7B8%20%2A14.3%20%5E%7B2%7D%20%7D%7B2%7D%20%3D%204%20%2A204.49%20%3D%20817.96J)
.
Therefore Kinetic energy is 817.96J.
The electric potential at point A in the electric field= 0.099 x 10 ⁻¹v
<u>Explanation</u>:
Given data,
charge = 5.5 x 10¹² C
k =9.00 x 10⁹
The electric potential V of a point charge can found by,
V= kQ / r
Assuming, r=5.00×10⁻² m
V= 5.5 x 10⁻¹²C x 9.00 x 10⁹ / 5.00×10⁻² m
V= 49.5 x 10⁻³/ 5.00×10⁻²
Electric potential V= 0.099 x 10⁻¹v
Answer:
t_total = 23.757 s
Explanation:
This is a kinematics exercise.
Let's start by calculating the distance and has to reach the limit speed of
v = 18.8 m / s
v = v₀ + a t₁
the elevator starts with zero speed
v = a t₁
t₁ = v / a
t₁ = 18.8 / 2.40
t₁ = 7.833 s
in this time he runs
y₁ = v₀ t₁ + ½ a t₁²
y₁ = ½ a t₁²
y₁ = ½ 2.40 7.833²
y₁ = 73.627 m
This is the time and distance traveled until reaching the maximum speed, which will be constant throughout the rest of the trip.
x_total = x₁ + x₂
x₂ = x_total - x₁
x₂ = 373 - 73,627
x₂ = 299.373 m
this distance travels at constant speed,
v = x₂ / t₂
t₂ = x₂ / v
t₂ = 299.373 / 18.8
t₂ = 15.92 s
therefore the total travel time is
t_total = t₁ + t₂
t_total = 7.833 + 15.92
t_total = 23.757 s
Answer:
B= 3.33 m T
Explanation:
Given that
Speed ,C= 6 x 10⁶ m/s
d= 1 cm = 0.01 m
V= 200 V
The electric field E given as
V= E .d
E=Electric field
d=Distance
V=Voltage
200 = 0.01 x E
E=20000 V/m
The relationship between magnetic and electric field given as
E= C x B
20000 = 6 x 10⁶ x B
B =3333.333 x 10⁻⁶ T
B= 3.33 x 10⁻³ T
B= 3.33 m T
Therefore the magnetic filed will be 3.33 m T.