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Ksju [112]
2 years ago
14

A note is being played on a string on a guitar. The string is then pushed to the side while still in contact with the same fret.

What happens to the frequency of the note then played compared to the original note?
Physics
1 answer:
Brut [27]2 years ago
3 0

Answer:

See explanation

Explanation:

- When the string is pressed on a particular fret, the note is the same. That's because the string will sound from bridge to that fret-wire. It's always the same distance, so will always be the same note.

- Frets is that it splits the fingerboard into discrete diatonic parts, and well made fret-boards will mean the same note gets played on the same fret on the same string every time.

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A person jumps from the roof of a house 3.1-m high. When he strikes the ground below, he bends his knees so that his torso decel
Sveta_85 [38]
Part A

Free fall motion
h = 3.1 m

Equation: Vf = √(2gh) = √(2*9.8 m/s^2 * 3.1 m) = 7.8 m/s

That is the only part in the question.
3 0
3 years ago
In a chemical reaction, the bonds in the molecules
notsponge [240]

Answer:

B. change

Explanation:

In a chemical reaction, the bonds in the molecules break apart and form new ones, thus b is the correct answer because they change.

6 0
2 years ago
Read 2 more answers
Given the equation p2 = a3, what is the orbital period, in days, for the planet venus? (venus is located 0.72 au from the sun?)
melisa1 [442]

The correct answer is 223 days.

The relationship between the duration of revolution and the separation between the sun is shown by Kepler's third law. Using the notions of circular motion and the gravitational and centripetal forces, we may obtain this equation.

According to Kepler's third rule, the semi-major axis of an orbit is linked to the orbital period of a planet around the sun as follows:

p² = a³

where an is the semi-major axis/distance to the star and p is the orbital period in years.

It is said that a = 0.72 AU for Venus.

P= √(0.72 AU)^3 = 0.61 years.

365 days in a year = 222.9 ≈ 223 days.

To learn more about Kepler's third rule refer the link:
brainly.com/question/1608361

#SPJ4

5 0
1 year ago
An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds. Which describes the acceleration? negati
hammer [34]

Answer:

we could use the formula, v=u+at,

65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2

5 0
3 years ago
the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

F_{net} = 51 N

now we also know that friction force due to ground is given as

F_f = 24 N

now we have

F_{net} = F_{ext} - F_f

51 = F_{ext} - 24

F_{ext} = 75 N

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

a = \frac{F_f}{m}

a = \frac{24}{24} = 1 m/s^2

now we can find the distance by kinematics

v_f^2 - v_i^2 = 2 a d

0 - 1.5^2 = 2(-1)d

d = 1.125 m

so the distance moved will be 1.125 m

6 0
3 years ago
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