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3 years ago

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ElectroMagnetic---WaveLength Range (Meters)

1 answer:

MrRa [10]3 years ago

4 0

Electronegativity, symbol χ, measures the tendency of an atom to attract a shared pair of electrons (or electron density). An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.

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A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s

user100 [1]

7.2 m/s

49 degrees south of west

7 0

3 years ago

Read 2 more answers

Ok, so this question is probably really easy but I can't really be bothered to answer it, terrible I know, but I thank all usefu

Dvinal [7]

Without a bulb energy cant go through and it would be an open circuit blocking the energy from coming out.

3 0

3 years ago

g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

sdas [7]

Answer:

The vertical distance is $d = \frac{2}{k} *[mg + f]$

Explanation:

From the question we are told that

The mass of the cylinder is m

The kinetic frictional force is f

Generally from the work energy theorem

$E = P + W_f$

Here E the the energy of the spring which is increasing and this is mathematically represented as

$E = \frac{1}{2} * k * d^2$

Here k is the spring constant

P is the potential energy of the cylinder which is mathematically represented as

$P = mgd$

And

$W_f$ is the workdone by friction which is mathematically represented as

$W_f = f * d$

So

$\frac{1}{2} * k * d^2 = mgd + f * d$

=> $\frac{1}{2} * k * d^2 = d[mg + f ]$

=> $\frac{1}{2} * k * d = [mg + f ]$

=> $d = \frac{2}{k} *[mg + f]$

5 0

3 years ago

Two pianos each sound the same note simultaneously, but they are both out of tune. On a day when the speed of sound is 349 m/s,

SSSSS [86.1K]

Answer:

Time period between the successive beats will be 0.1703 sec

Explanation:

We have given speed of the sound v = 349 m/sec

Wavelength of piano $A\lambda _A=0.766m$

Wavelength of piano $B\lambda _B=0.776m$

So frequency of piano A $f_1=\frac{v}{\lambda _1}=\frac{349}{0.766}=455.61Hz$

Frequency of piano B $f_2=\frac{v}{\lambda _1}=\frac{349}{0.776}=449.74Hz$

So beat frequency f = 455.61 - 449.74 = 5.87 Hz

So time period $T=\frac{1}{f}=\frac{1}{5.87}=0.1703sec$

So time period between the successive beats will be 0.1703 sec

4 0

3 years ago

A ship sails west for 100km and then south for 100km. What is the displacement?

ale4655 [162]

$\sf \vec{w}=100$

$\sf \vec{s}=100$

For displacement apply Pythagorean theorem

$\\ \rm\hookrightarrow 100^2+100^2$

$\\ \rm\hookrightarrow 10000+10000$

$\\ \rm\hookrightarrow 20000$

4 0

2 years ago