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scoundrel [369]
1 year ago
8

Need help asap

Physics
1 answer:
Vanyuwa [196]1 year ago
8 0
I’ve done this before the answer is B
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Which of these is NOT a vector quantity?
Vlada [557]
The answer to that question is c. acceleration due to gravity

3 0
3 years ago
What is the velocity of a bobsled that travels 100 meters in 8.9 seconds in m/s
mart [117]

Answer:

11.2 m/s

Explanation:

Average velocity = displacement / time

v = 100 m / 8.9 s

v = 11.2 m/s

7 0
3 years ago
A 3.53-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. find percent composition
katrin2010 [14]

The mass percent composition of aluminum is 52.9% in aluminum oxide.

Mass of the aluminum = 3.53 g

Mass of the aluminum oxide = 6.67 g.

The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.

Aluminum reacts with oxygen to form aluminum oxide.

The overall balanced equation for the reaction is,

Aluminum + Oxygen→Aluminum \: oxygen

4Al +3O _{2}→2Al _{2}O _{3}

The mass percent composition of aluminum in the aluminum oxide is,

Mass  \: percent = \frac{ Mass \:  of \:  the  \: substance}{ Mass  \: of \:  the \:  compound} \times 100

Mass  \: percent =  \frac{Mass  \: of \:  the  \: aluminum}{ Mass \:  of \:  the \:  aluminum \: oxide } \times 100

Mass \:  percent  =  \frac{3.53}{6.67 } \times 100

= 52.9 %

Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.

To know more about aluminum oxide, refer to the below link:

brainly.com/question/25869623

#SPJ4

7 0
2 years ago
What wires allow electrons to flow the easiest?
docker41 [41]
The shortest and straight ones
5 0
3 years ago
Si un cuerpo adquiere una carga de -0,02 C, ha ganado o ha perdido electrones? Cuantos?
sammy [17]

Question :

If a body acquires a charge of -0.02 C, has it gained or lost electrons? Many?

Solution :

We know, charge gained is shown by negative sign.

Since, charged acquired is given as -0.02 C .

Therefore, it is body has gained electrons.

Now, number of electrons is given by :

n = \dfrac{net\ charge}{charge \  on \ one \  electron}\\\\n = \dfrac{-0.02}{-1.60 \times 10^{-19}}\\\\n = 1.25\times 10^{17}

Hence, this is the required solution.

7 0
3 years ago
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