Answer:
So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.
Explanation:
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Answer:
second month = 0.5² = 1/4 of original
third month = 0.5³ = 1/8 of original
Explanation:
Answer:
2,500,000 MJ (
)
Explanation:
According to the work-energy theorem:
The work done on an object is equal to the amount of energy transferred
In this problem, the energy transferred by the rocket is
Therefore, the work done must be equal to the energy transferred, therefore:
Answer:
Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.
Hence, for series combination of resistances,
R
s
=2R
And for parallel combination of resistances,
R
p
=
2
R
Now, heat produced when they first connected in series is
H
s
=
R
s
V
2
where, V is voltage supplied to the heater.
H
s
=
2R
V
2
.....................................(1)
heat produced when they first connected in series is
H
p
=
R
p
V
2
H
p
=
2
R
V
2
H
p
=
R
2V
2
............................................(2)
From (1) and (2), we get
H
p
H
s
=
R
2V
2
2R
V
2
⇒
H
p
H
s
=
4
1
