Since D=M/V, the answer would be 2.7
Answer:
a) x = 4.33 m
, b) w = 2 rad / s
, f = 0.318 Hz
, c) a = - 17.31 cm / s²,
d) T = 3.15 s, e) A = 5.0 cm
Explanation:
In this exercise on simple harmonic motion we are given the expression for motion
x = 5 cos (2t + π / 6)
they ask us for t = 0
a) the position of the particle
x = 5 cos (π / 6)
x = 4.33 m
remember angles are in radians
b) The general form of the equation is
x = A cos (w t + Ф)
when comparing the two equations
w = 2 rad / s
angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 2 / 2pi
f = 0.318 Hz
c) the acceleration is defined by
a == d²x / dt²
a = - A w² cos (wt + Ф)
for t = 0
, we substitute
a = - 5,0 2² cos (π / 6)
a = - 17.31 cm / s²
d) El period is
T = 1/f
T= 1/0.318
T = 3.15 s
e) the amplitude
A = 5.0 cm
<span>Amplitude is the correct answer. I hope this helps.</span>
Answer:
Explanation:
mass (m1) = 1150 kg
mass (m2) = 1900 kg
impulse (J) = 200 N.s
With what relative speed do the two parts separate because of the detonation?
since both parts separate, their relative speed = speed of m1 + speed of m2
- speed of m1 =
= 
= 0.174 m/s
- speed of m2 = =
= 0.105 m/s - relative speed = 0.174 + 0.105 = 0.279 m/s
Answer:
In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
