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3 years ago

What effect does an increase in temperature have on viscosity?

2 answers:

4 0

The former effect causes a decrease in the shear stress while the latter causes it to increase. The result is that liquids show a reduction in viscosity with increasing temperature. With high temperatures, viscosity increases in gases and decreases in liquids, the drag force will do the same.

Bogdan [553]3 years ago

3 0

Gravitational acceleration aka Weight

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A flat horizontal surface with an area of 518 cm^2 is inside a uniform electric field of 1.33 x 10^4 N/C. The angle between the

GarryVolchara [31]

Answer: 576.48 N*m^2/C

Explanation: In order to calculate the electric flux through the any surface we have to take into account the scalar product between the electric field vector and the normal vector to the surface.

So we have:

ФE= E*A= 1.33 * 10^4*0.0518* cos (33.2°)= 576.48 N*m^2/C

3 0

3 years ago

If the mass of a

mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

$F=ma$

m = mass

a = acceleration

According to given condition, if the mass of a sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

$a=\dfrac{F}{m}$

Let a' is the final acceleration,

$a'=\dfrac{F}{m'}$

m' = 3m

$a'=\dfrac{F}{3m}$

$a'=\dfrac{1}{3}\times \dfrac{F}{m}$

$a'=\dfrac{1}{3}\times a$

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0

3 years ago

A 1000.kg car moving at north at 100. km/hr brakes to a stop in 50. m within a uniform acceleration. what are magnitude and dire

Marianna [84]

Answer:

Force=7.71KN in the opposite direction

Explanation:

Given the mass of the car(M)=1000Kg

The initial speed of the car(u)=100km/hr

we know that 1km/hr=5/18 m/sec

100km/hr=100*5/18 m/sec=27.77m/sec

the distance travelled before it stops (s)=50m

let the acceleration of the car be a

The final velocity of the car is 0.

we know that $v^{2}-u^{2}=2as$

$0^{2}-27.77^{2}=2(-a)(50)$

a=7.712m/ $sec^{2}$

We know that F=Ma

F=1000* 7.712=7712N=7.71KN

6 0

3 years ago

Pleae answer asap brcianset

marshall27 [118]

Answer:

Explanation:

1/8 is greater than 3/20

5 0

3 years ago

A force is applied to a 30-kg object, resulting in an acceleration of 15 m/s. What is the force being applied to the object?

telo118 [61]

The sum of all forces applied to the object = (mass) x (acceleration)

The sum of all forces applied to the object = (30) x (15)

= <u>450 newtons</u>, in the direction of the acceleration.

5 0

3 years ago

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