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3 years ago

The most abundant element in earth's continental crust (by weight) is____?

Physics

2 answers:

sashaice [31]3 years ago

8 0

The answer is A. Oxygen

AlekseyPX3 years ago

5 0

Answer: A. Oxygen

Explanation: Oxygen is the most abundant element in the Earth's crust by weight. Oxygen amounts to 46.6% of the Earth's crust by weight.

Oxygen is a major compound of the silicate minerals where it reacts with other elements. Oxygen can he will receive bottling collected pls, he will pretence as a compound in carbonates and phosphates. Oxygen has industrial, medical, and commercial purposes. It is used with acetylene to cut and weld metals. It is used in hospitals to ease respiratory disease and can also be used to manufacture explosives among other numerous uses.

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In a velocity selector having electric field E and magnetic field B, the velocity selected for positively charged particles is v

maw [93]

Answer:

True or False

Explanation:

Because.....

easy 50% chance you are right

6 0

3 years ago

An object is thrown straight up into the air with an initial speed of 8 m/s, and reaches a greatest height of 15 m before it fal

Ugo [173]

Answer:

The value is $T_t = 2.5659 \ s$

Explanation:

From the we are told that

The initial speed of the object is $u = 8 \ m/s$

The greatest height it reached is $h = 15 \ m$

Generally from kinematic equation we have that

$v^2 = u^2 + 2gH$

At maximum height v = 0 m/s

$0^2 = 8^2 + 2 * - 9.8 * H$

=> $H = 3.27 \ m$

Here H is the height from the initial height to the maximum height

So the initial height is mathematically represented as

$s = h - H$

=> $s = 15 - 3.27$

=> $s = 11.73 \ m$

Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows

$v = u + (-g) t$

At maximum height v = 0 m/s

$0 = 8 - 9.8t$

=> $t = 0.8163 \ s$

Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows

$h = ut_1 + \frac{1}{2} gt_1^2$

Here the initial velocity is 0 m/s given that its the velocity at maximum height

Also g is positive because we are moving in the direction of gravity

$15 = 0* t + 4.9 t^2$

=> $t_1 = 1.7496$

Generally the total time taken is mathematically represented as

$T_t = t + t_1$

=> $T_t = 0.8163 + 1.7496$

=> $T_t = 2.5659 \ s$

6 0

3 years ago

If the energy from the light is captured and stored by the surface without being reflected or transmitted, then it has been ____

vekshin1

A. ABSORBEDDDDDDDDDDDDDDDDDD

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3 years ago

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Free point cuz i cewl like dat‍♀️‍♂️

DedPeter [7]

Yes thank u teehee

.................... x

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2 years ago

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You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?

Snezhnost [94]

If you are pushing the coin across the table at a constant rate, the friction of the table and the horizontal force of your hand pushing are equal, and the coin itself moves at a constant rate. If you push a coin and let it go, there is no horizontal force keeping the coin going. Friction slows the coin to a stop. In both cases, the gravitational downward pull of Earth is equally but oppositely resisted by the upward push of table on the coin.

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3 years ago