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VikaD [51]
3 years ago
11

A pendulum with a period of 1 s on earth where the acceleration

Physics
1 answer:
Svetradugi [14.3K]3 years ago
6 0
A pendulum with a period of ones on earth where the acceleration
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HELP...<br> 3.00 amu = _____ Mev.<br><br> 3.22 x 10-3<br> 2.79 x 103<br> 3.10 x 102
DanielleElmas [232]
The correct answer is:
2.79 \cdot 10^3 MeV
Let's see why.

1 amu corresponds to the mass of the proton, which is:
m_p = 1.66 \cdot 10^{-27} kg
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
E=mc^2 = (1.66 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2 = 1.49 \cdot 10^{-10} J
Now we can convert it into electronvolts:
E= \frac{1.49 \cdot 10^{-10}kg}{1.6 \cdot 10^{-19} J/eV} =9.34 \cdot 10^9 eV = 934 MeV

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
3 amu = 3 \cdot 934 MeV  \sim 2790 MeV = 2.79 \cdot 10^3 MeV
5 0
3 years ago
Read 2 more answers
In everyday situations, it does seem that a force is needed to keep an object, for example the shopping trolley, moving at a con
Jobisdone [24]

Answer:

Because of friction

Explanation:

7 0
2 years ago
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A package is pushed across the floor a distance of 90 feet by exerting a force of 32 lbs downward at an angle of 24 ∘ with the h
Crazy boy [7]

Answer:

2632 foot-pound

Explanation:

Work done: Work is said to be done when ever a force moves a body through a given distance. The S.I unit of force is Newton (N).

From the question,

The expression for work done is given as,

W = Fdcos∅......................... Equation 1

Where W = work done, F = force, d = distance, ∅ = angle between the force and the horizontal.

Given: F = 32 lbs, d = 90 feet, ∅ = 24°

substitute into equation 1

W = 32×90×cos24

W = 2880(0.914)

W = 2632.32

W = 2632 foot-pound

4 0
3 years ago
Joanne drives her car with a mass of 1000 {\rm kg} at a speed of 23m/s .
rosijanka [135]
F = ma = 1000*(23-0)/14 = 1642.86 N
5 0
3 years ago
How many atoms of hydrogen in the product side of the balanced equation
Anettt [7]

The same number there were on the reactant side, before the reaction.

6 0
3 years ago
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