Answer:
flux=13.92W/m^2
Explanation:
The heat transfer by conduction consists in the transport of energy through particles that are together, that is to say by means of solids, Newton developed an equation that allows to know the heat transported in a flat plate knowing the cross sectional area A, Thickness L, conductivity K and a temperature difference between the internal and external surface.
Q=KA(t2-t1)/L
To know the heat flux we simply divide both sides of the equation by the area.
Flux=K(t2-t1)/L
where
K=0.029w/mk
L=25mm=0.025m
t2-t1=12 ° C
solving
Flux=(0.029)(12)/(0.025)
flux=13.92W/m^2
Answer:
1g/cm3
Explanation:
volume of block is 3 cubed which is 27 cm3
we know density is m/v so d= 27g/27cm3
which is 1g/cm3
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Answer:
d) The speed of the astronaut
Explanation:
The sentence describes the speed of the astronaut. This speed value is 10meters per minute.
Now let us understand why;
- Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude.
- The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards.
- Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion.
- For example, 10m/s due west is a velocity value because we know the direction.
Therefore, since there is no directional sense, the value indicates speed.
Answer:
A. 3.4 m
Explanation:
Given the following data;
Force = 56.7N
Workdone = 195J
To find the distance
Workdone is given by the formula;
Making "distance" the subject of formula, we have;

Substituting into the equation, we have;

Distance = 3.4 meters.
Answer:
The change in internal energy of the system is -17746.78 J
Explanation:
Given that,
Pressure 
Remove heat 
Radius = 0.272 m
Distance d = 0.163 m
We need to calculate the internal energy
Using thermodynamics first equation
...(I)
Where, dU = internal energy
Q = heat
W = work done
Put the value of W in equation (I)

Where, W = PdV
Put the value in the equation


Hence, The change in internal energy of the system is -17746.78 J