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NNADVOKAT [17]
4 years ago
9

In what direction would the new b field point?

Physics
1 answer:
Aleonysh [2.5K]4 years ago
7 0
Please include more information about the problem. What "b field" are you talking about? What is different about it from the previous field?
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Object A is negatively Charged. object A and Object B attract. Object B and Object C repel. Object C and Object D attract. What
3241004551 [841]

Remember opposites attract and same charges repel each other.

Object A= negatively charged.

Object A and B attract so B must be positively charged.

Object B and C repel so because B is positively charged C must also be positively charged.

Object C and D attract and because C is positively charged, D must be negatively charged.

5 0
4 years ago
Can someone help me this question ​
vladimir2022 [97]

Answer:

Volume of wood is 68-50 = 18 cm³

Explanation:

<h2>Hope it helps you</h2>
4 0
3 years ago
Use the diagram to answer each question.
HACTEHA [7]
At E the potential energy is maximum/highest. The potential energy decreases as it goes down and increases as it goes up. so if the pendulum swinged from E to A, potential energy would decrease till C and increase till A.
7 0
3 years ago
A cube 10.0 cm on each side has a density of 2.053 x 10^4 kg/m^3. It’s apparent weight in fresh water is 192 N. Find the buoyant
insens350 [35]

Answer:

9 N

Explanation: Given that L = side of the cube = 10cm = 0.1m

Mass = Density * Volume

Let’s determine the volume of the cube in m^3.

V = L^3

V = 0.1^3 = 0.001m^3

Mass = 0.001 * 2.053 * 10^4 = 20.53kg

Weight = 20.53 * 9.8 = 201.194

Buoyant force = 201.194 – 192 = 9.194 N

This is approximately 9 N.

6 0
4 years ago
Two objects each with a mass of 5x10^15 kg have a gravitational
kipiarov [429]

Answer:

Distance, r = 700.31 m

Explanation:

Mass of two objects, m_1=m_2=5\times 10^{15}\ kg

Force between the objects , F=3.4\times 10^{15}\ N

We need to find the distance between the two objects. The force of gravitational between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\r=\sqrt{\dfrac{Gm_1m_2}{F}} \\\\r=\sqrt{\dfrac{6.67\times 10^{-11}\times (5\times 10^{15})^2}{3.4\times 10^{15}}}\\\\=700.31\ m

So, the distance between the objects is 700.31 m.

6 0
3 years ago
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