A cube 10.0 cm on each side has a density of 2.053 x 10^4 kg/m^3. It’s apparent weight in fresh water is 192 N. Find the buoyant force.
1 answer:
Answer:
9 N
Explanation: Given that L = side of the cube = 10cm = 0.1m
Mass = Density * Volume
Let’s determine the volume of the cube in m^3.
V = L^3
V = 0.1^3 = 0.001m^3
Mass = 0.001 * 2.053 * 10^4 = 20.53kg
Weight = 20.53 * 9.8 = 201.194
Buoyant force = 201.194 – 192 = 9.194 N
This is approximately 9 N.
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Answer:
10 W
Explanation:
P = F x v
F = 200N
v = x2 - x1 / t
= 6 - 3 / 60
= 3 / 60
= 1 / 20
= 0.05 m/s
P = 200 x 1/20
= 10 W
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