What is the organ(s) that detect taste

Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 6 cm and 4 cm.

Butoxors [25]

Answer:

Minimum Area of rectangle = 24 centimeter²

Explanation:

Given:

Length of rectangle = 6 centimeter

Width of rectangle = 4 centimeter

Find:

Minimum Area of rectangle

Computation:

Minimum Area of rectangle = Length of rectangle x Width of rectangle

Minimum Area of rectangle = 6 x 4

Minimum Area of rectangle = 24 centimeter²

7 0

3 years ago

Two concentric conducting spherical shells produce a radially outward electric field of magnitude49,000 N/C at a point 4.10 m fr

Korolek [52]

To solve this problem it is necessary to apply the concepts related to the electric field according to the definition of Coulomb's law.

The electric field is defined mathematically as a vector field that associates to each point in space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point.

Mathematically this can be described as:

$E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}$

Where,

$\epsilon_0 =$ permittivity of free space

r = Distance

q = Charge

E = Electric Field

Our values are given as,

$E= 49.000N/C$

$r= 4.1m$

$\epsilon_0=8.854*10{-12}C^2N^{-1}m^{-2}$

Replacing we have,

$E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}$

$49000 = \frac{1}{4\pi (8.854*10{-12})}\frac{q}{(4.1)^2}$

$q= 9.16*10^{-5} C$

$q= 91.6\mu C$

Therefore the amoun of charge on the outer surface of the larger shell is $91.6 \mu C$

6 0

3 years ago

A bicycle pedal is pushed straight downwards by a foot with a 33 Newton force. The shaft of the pedal is 20 cm long. If the shaf

katen-ka-za [31]

Answer:

The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm

Explanation:

The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:

T = d * Fp

Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:

Fp = F*sin(a)

Replacing the values for the force and the angle:

Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N

Taking the distance in meters:

T = 0.2m * 0.363 N = 0.063 Nm

7 0

3 years ago

A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator? 5

Gre4nikov [31]

Answer:

T = 4000 N

Explanation:

We have,

Mass of an elevator, m = 500 kg

It is moving downward with an acceleration of $2\ m/s^2$ . It is required to find the tension force of the cable on the elevator. We know that when the elevator is moving downward, the net force on it is given by :

$F=m(g-a)$

g is acceleration due to gravity

$F=500\times (10-2)\\\\F=4000\ N$

So, the tension force of the cable on the elevator is 4000 N.

5 0

3 years ago

How many resonance structures does aniline have after the first step of electrophilic aromatic substitution?

professor190 [17]

Answer:

Electrophilic aromatic substitution involves a process in an atom that is attached to an aromatic system is replaced by a electrophile. Electrophile is an electron pair acceptor. In the first step of electrophilic aromatic substitution of aniline, aniline has 3 resonance structures.

Explanation:

Aniline undergo a two step electrophilic aromatic substitution. The first step yields both ortho and para groups while the last yield a meta group.

In the first step, the amino group of aniline are strong activating group and ortho/para directing by resonance. This amino groups donates their unshared electrons to the pi-system creating a negative charge on the ortho and para positions. These positions are most reactive towards an electron-poor electrophile.

In the second step, the electrophilic aromatic substitution on aniline proceeds quite slowly to give an unexpected high yield of meta product.

8 0

3 years ago