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4 years ago

What is the organ(s) that detect taste

Physics

1 answer:

Nata [24]4 years ago

6 0

Your taste buds that are located on your tongue

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Which is an example of velocity?

Dima020 [189]

I think the answer is A

3 0

3 years ago

A uniform meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 5 s. The meter stick

rewona [7]

Answer:

The new time period is $T_2 = 3.8 \ s$

Explanation:

From the question we are told that

The period of oscillation is $T = 5 \ s$

The new length is $l_2 = 0.76 \ m$

Let assume the original length was $l_1 = 1 m$

Generally the time period is mathematically represented as

$T = 2 \pi \sqrt{ \frac{ I }{ mgh } }$

Now I is the moment of inertia of the stick which is mathematically represented as

$I = \frac{m * l^2 }{12 }$

$T = 2 \pi \sqrt{ \frac{ m * l^2 }{12 * mgh } }$

Looking at the above equation we see that

$T \ \ \ \alpha \ \ \ l$

=> $\frac{ T_2 }{T_1} = \frac{l_2}{l_1}$

=> $\frac{ T_2}{5} = \frac{0.76}{1}$

=> $T_2 = 3.8 \ s$

3 0

4 years ago

A torsion pendulum consists of an irregularly-shaped object of mass 20.0 kg suspended vertically by a wire of torsion constant 0

netineya [11]

Answer:

Rotational inertia of the object is, $I=0.023\ kg-m^2$

Explanation:

Given that,

Mass of the object, m = 20 kg

Torsion constant of the wire, K = 0.85 N-m

Number of cycles, n = 69

Time, t = 66 s

To find,

The rotational inertia of the object.

Solution,

There exists a relationship between the moment of inertia, time period and the torsion constant of the spring is given by :

$T=2\pi\sqrt{\dfrac{I}{K}}$

Here I is the moment of inertia

T is the time period, and it is equal to the number of cycles per unit time

$I=\dfrac{T^2K}{4\pi ^2}$

$I=\dfrac{(69/66)^2\times 0.85}{4\pi ^2}$

$I=0.023\ kg-m^2$

So, the rotational inertia of the object is $0.023\ kg-m^2$ .

7 0

4 years ago

Black holes must have a mass _____ or more times the mass of the Sun.

statuscvo [17]

<span>Black holes must have a mass THREE or more times the mass of the Sun.</span>

8 0

4 years ago

a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find th

elena-s [515]

Answer: 24 kN

Explanation:

Given

The rocket burns propellant at the rate of

$\dfrac{dm}{dt}=3\ kg/s$

Relative ejection of gases $v=8000\ m/s$

The magnitude of thrust force is given by

$F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN$

5 0

3 years ago