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valentinak56 [21]
3 years ago
13

Sodium acetate never precipitates True or False?

Chemistry
2 answers:
I am Lyosha [343]3 years ago
4 0

Answer:

It is indeed true, Sodium acetate never precipitates

Reptile [31]3 years ago
3 0

Answer:

it is false Sodium acetate NEVER precipitates

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A sample of gas weighs 10.1 g and occupies a volume of 5.65 l at 60 °c and 580 torr. Identify the gas sample.
OverLord2011 [107]

The question is incomplete, here is the complete question:

A sample of gas weighs 10.1 g and occupies a volume of 5.65 L at 60 °C and 580 torr. Identify the gas sample.

(a) CHCl_3 (molar mass = 119.4 g/mol)  

(b) N_2O (molar mass = 44.02 g/mol)

(c) SO_2 (molar mass = 64.07 g/mol)

(d) NH_3 (molar mass = 17.03 g/mol)

(e) Cl_2 (molar mass = 70.90 g/mol)

<u>Answer:</u> The gas sample is SO_2 having molar mass of 64 g/mol

<u>Explanation:</u>

To calculate the molar mass of the gas, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 580 torr

V = Volume of the gas = 5.65 L

w = Weight of the gas = 10.1 g

M = Molar mass of gas = ?

R = Gas constant = 62.36\text{ L. Torr }mol^{-1}K^{-1}

T = Temperature of the gas = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

580torr\times 5.65L=\frac{10.1g}{M}\times 62.364\text{ L. torr }mol^{-1}K^{-1}\times 333K\\\\M=\frac{10.1\times 62.364\times 333}{580\times 5.65}=64g/mol

Hence, the gas sample is SO_2 having molar mass of 64 g/mol

4 0
3 years ago
Which is the correctly balanced equation for the reaction of rust, fe2o3, and hydrochloric acid, hcl?.
kap26 [50]

Answer:

fe2o3 + 6hcl => 2fecl3 + 3h2o

Explanation:

7 0
3 years ago
What is energy?
Nat2105 [25]
The answer would be the second answer: the property that gives it mass. This is because energy is t<span>he property of an object or system that enables it to do work. </span>
5 0
3 years ago
Read 2 more answers
Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have
Zepler [3.9K]

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g}  = 59.1\frac{\$}{g}

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g

Thus, the price is:

\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$

Best regards!

7 0
4 years ago
I'll give u thirty points
salantis [7]
I hope this helps answer some of your questions.

3 0
3 years ago
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