The % mass/mass concentration of solute in the seawater sample is calculated as below
% mass = mass of the solute /mass of the solvent(sea water) x100
mass of the solute =1.295 g
mass of the solvent(sea water_) = 25.895 g
there the % mass = 1.295/25.895 x100 = 5.001 %
Answer:chlorofluorocarbons (CFCs)
halon.
carbon tetrachloride (CCl4)
methyl chloroform (CH3CCl3)
hydrobromofluorocarbons (HBFCs)
hydrochlorofluorocarbons (HCFCs)
methyl bromide (CH3Br)
bromochloromethane (CH2BrCl)
Explanation:
BRAINLIEST pls
Question: The question is not complete. Find below the complete question and the answer.
Alab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? mL
Volume of 20% solution= ?
Volume of 26% solution = ?
Volume of 42% solution= ? Round to the nearest whole number ml
Answer:
Volume of 20% solution= 3 mL
Volume of 26% solution = 1 mL
Volume of 42% solution= 10 mL
Explanation:
Find attached of the calculations.
Answer:
PROTON AND NEUTRON
Explanation:
- The mass of proton is :

A proton is one of the main particles that make up the atom . The other two particles are neutron and electron. Protons are found in the nucleus of the atom.This is a tiny , dense region at the centre of the atom. Protons have a positive charge of one (+1) and a mass of 1 atomic mass unit ( amu ) , which is about
. Together with neutrons , they make up virtually all of the mass of an atom.
- The mass of neutron is also approximately:
but a little more than that .
Atoms of all elements - except Hydrogen , have neutrons in their nucleus . Unlike protons and electrons , these have no charge - they are electrically neutral . The mass of a neutron is slightly greater than the mass of a proton but not very significant
Answer:
.0556 L
Explanation:
First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.
Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).
Finally, the answer will be .0556 L.
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