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Mariana [72]
3 years ago
15

Introduction This section describes the principles and concepts related to the experiment. It is used to help the person reading

your report to understand the information that serves as foundation for the experiment. It also includes a brief statement about the purpose of the lab. Example: Surface tension is the attractive force exerted upon the surface molecules of a liquid by the molecules beneath. Water has a high surface tension because there are strong attractive forces between water molecules. Adding surfactants, like soap, can reduce the surface tension of a liquid. The purpose of the experiment was to determine the effect of soap on the surface tension of water.
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

See explanation

Explanation:

It is a common observation that when water drops on a clean glass surface, it appears as little bags of water.

Surface tension makes water surface act like a stretched elastic skin bag.

Surface tension is caused by attractive forces between the molecules at the surface and the molecules in the bulk of a liquid. Remember that the forces of cohesion between water molecules are very strong.

When surfactants such as soap are added to water, the surface tension of water is decreased, hence the experiment.

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What is the momentum of a 1400 kg car traveling at 25 m/s?
sveticcg [70]
<h2>Hello</h2>

The answer is:

35000Kg.\frac{m}{s}=35000N

<h2>Why?</h2>

Momentum is the quantity of movement of an object, and it's calculated using the mass and the velocity of the object. Momentum is expressed by the following formula:

p=m*v

Where:

m=mass\\v=velocity

So, calculating we have:

p=m*v=1400Kg*\frac{25m}{s}=35000Kg.\frac{m}{s}=35000N

Remember,

1N=1Kg.\frac{m}{s}

Have a nice day!

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3 years ago
At the presentation ceremony, a championship bowler is presented a 1.60-kg trophy which he holds at arm's length, a distance of
nikdorinn [45]

Answer:

a)10.28 Nm

b)9.93 Nm

Explanation:

Let g = 9.81m/s2. First we can calculate the weight of the trophy

W = mg = 1.6 * 9.81 = 15.696 N

(a) The torque is product of force and its moment arm

T = WL = 15.696 * 0.655 = 10.28 Nm

(b) Suppose his arm makes an angle of 15 degree with respect to the horizontal line. We can still calculate the arm length, or the horizontal distance from the trophy to the champion:

L_2 = Lcos(15^0) = 0.655cos(15^0) = 0.655*0.966 = 0.633 m

Again, torque is product of force and its moment arm

T_2 = WL_2 = 15.696 * 0.633 = 9.93 Nm

8 0
3 years ago
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