Ask question

Ask question

All categories

3 years ago

8

A crate is dragged 4.0m along a rough floor with a constant velocity by a worker applying a force of 400N to a rope at an angle

of 30∘ to the horizontal.

1 answer:

andrew11 [14]3 years ago

5 0

OK. We've got that much. The worker does 1,385.6 joules of work
on the crate. What is your question ?

You might be interested in

A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. (a) What is the acceleration exp

givi [52]

Yes the plot dose make it with out baking out

7 0

4 years ago

Explain you own words why energy is considered to be naturals money. Give an example to support your explanation

max2010maxim [7]

Answer:

because we naturally use energy everyday in everyway , energy is also a bill for instance you electric bill used by energy

Explanation:

8 0

3 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$

Generelly

$KE_b = \frac{1}{2} m v^2$

And $PE_b = q V_a$

Equating this two formulas

$\frac{1}{2} mv^2 = q V_a$

making v the subject

$v = \sqrt{\frac{q V_a}{2 m} }$

Substituting value

$v = \sqrt{\frac{ 2* 1.602 *10^{-19} * 1.8 *10^{3}}{2 * 6.64 *10^{-27}} }$

$v = 41.65*10^4 m/s$

Generally the electric field between the plates is mathematically represented as

$E = \frac{V_b}{d}$

Substituting value

$E = \frac{120}{8*10^{-3}}$

$E = 15 *10^3 NC^{-1}$

the magnetic field is mathematically evaluate

$B = \frac{E}{v}$

$B = \frac{15 *10^{3}}{41.65 *10^4}$

$B = 0.0036T$

6 0

3 years ago

If the faster stone takes 12.0 s to return to the ground, how long will it take the slower stone to return?

iren [92.7K]

Same speed, because mass is neglected. The things that affect the speed are the distance and speed of the rock.

5 0

4 years ago

Which of the following is TRUE about cells?

Travka [436]

Answer:

All above!

Explanation:

Hope this helps!! :))

4 0

3 years ago