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Novay_Z [31]
3 years ago
14

A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with ne

arly the same speed with which it hit. The clay sticks to the wall. Which one of these objects experiences the greater momentum change?
Physics
1 answer:
gregori [183]3 years ago
3 0

Answer:

The ball experiences the greater momentum change

Explanation:

The momentum change of each object is given by:

\Delta p = m \Delta v= m (v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

Both objects have same mass m and same initial velocity u. So we have:

- For the ball, the final velocity is

v=-u

Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is

\Delta p=m(v-u)=m((-u)-u)=-2mu

- For the clay, the final velocity is

v=0

since it sticks to the wall. So, the change in momentum is

\Delta p = m(v-u)=m(0-u)=-mu

So we see that the greater momentum change (in magnitude) is experienced by the ball.

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kvasek [131]
Average speed = total distance / total time.

That's 172 km / 5 hr = 34.4 km//hr
5 0
3 years ago
A train travels 120 km in 2 hours and 30 minutes. What is its average speed
marissa [1.9K]

Answer:

48 kmph

Explanation:

The question is asking you the kmph and that means the amount of kilometers travelled divided by the amount of hours. And if you want to think of it in a formula, SPEED = DISTANCE ÷ TIME

In this case, the amount of hours is 2.5 and the speed is 120km so 120/2.5 is 48

so the answer is 48 kmph

5 0
3 years ago
Read 2 more answers
a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s . part a calculate its total kinet
erma4kov [3.2K]

49 J   is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.

Given:    m = 7.3 Kg ;  r = 9.4 cm = 0.094 m   ;   v = 3.1 m

Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation  + Kinetic energy due to translation

i,e     KE = 1/2*m*v2   +   1/2*I*ω2      where   I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity

Now for pure rotation (without slipping)    v = rω  

also for the ball (solid sphere)  I = 2/5*m*r2

Hence our kinetic energy becomes  

 KE = 1/2*m*v2 +  1/5*m*v2 = 7/10*m*v2

so   KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J

Learn more about kinetic energy here

brainly.com/question/12669551

#SPJ4

5 0
1 year ago
For each statement, circle whether it is true or false.
Tems11 [23]
A, got a 100 on my test
8 0
2 years ago
A 2.0-kg block sliding on a rough surface is attached to one end of a horizontal spring (k = 200 N/m) which has its other end fi
earnstyle [38]

Answer:

The speed is 3.87 m/s

Explanation:

The total work is equal to the change to kinetic energy:

Wtotal = ΔEk

Wspring + Wfriction = Ekf - Eki

Eki = 0

-(\frac{1}{2} kd^{2} )-(fk*m*g*d^{2} )=\frac{1}{2} m(v^{2} -v_{i} ^{2} )

Where

k = 200 N/m

d = 10 cm = 0.1 m

fk = 0.15

m = 2 kg

g = 9.8 m/s²

vi = 4 m/s

Replacing and clearing v:

-(\frac{1}{2} *200*0.1^{2} )-(0.15*2*9.8*0.1^{2} )=\frac{1}{2} *2*(v^{2} -4^{2} )\\-1-0.0294=v^{2}  -16\\v=\sqrt{-1-0.0294+16} =3.87m/s

3 0
3 years ago
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