Answer:
T2 = 135.1°C
Explanation:
Given data:
Mass of water = 96 g
Initial temperature = 113°C
Final temperature = ?
Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)
Specific heat capacity of aluminium = 0.897 j/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Now we will put the values in formula.
Q = m.c. ΔT
1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C
1900 j = 86.112 j/°C × T2 - 113°C
1900 j / 86.112 j/°C = T2 - 113°C
22.1°C + 113°C = T2
T2 = 135.1°C
Answer:
Fe is limiting, and it will produce .0188 mols of Fe2O3
Explanation:
after you convert both Fe and O2 to mols by using their molar mass, you see there is less Fe than O2 so that is your limiting reactant. To find the amount of Fe2O3 you devide the limiting reactant by it's coefeciant (4) then multiply it by the products coefficant (2). Let me know if you have any questions
Answer:
Ok to solve this you will need to use the Ideal Gas Law Formula which is as follows:
PV = nRT
P= pressure
V= volume
n= # of moles
R= Universal Gas Constant (0.0821 L x atm/mol x K)
T= Kelvin temperature
1.Simplify the Ideal Gas Law formula to what you need to solve for:
P = (nRT)/ V
2. List all you components as follows (this makes the process easier):
P = ?
V = 45.4 L
n = 0.625 mol
R = 0.0821 L x atm/ mol x K
T = 249 K
To find the Kelvin temperature K = C + 273
3. Plug in all your components in your set up formula:
P = [(0.625 mol)(0.0821 L x atm/ mol x K)(249 K)] / (45.4 L)
4. Cross out all similar units so the only thing left is atm because you are trying to find pressure.
P = [(0.625)(0.0821atm)(249)] / (45.4)
5. Multiply through and simplify
P = 0.28 atm
B. is the correct answer.
Glad I could help!! If you have any other questions just message me. Hopefully this was helpful.
Explanation:
Equation: 2H₂ + O₂ → 2H₂O
Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol
No. of moles in Oxygen = 16/192 = 0.0833
Now, for every mole of Oxygen, 2 mole of Hydrogen will form,
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167
Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g
In short, Your Answer would be: 0.33 g
Hope this helps!
Answer:
C. 33.6L
Explanation:
Based on the reaction, 2 moles of HCl reacts producing 1 mole of hydrogen.
To solve this question we must find the moles of hydrogen produced using the reaction. Then, with combined gas law (PV = nRT) we can find the volume produced:
<em>Moles H2:</em>
3.00 moles HCl * (1mol H2 / 2mol HCl) = 1.50 moles H2 are produced
<em>Volume:</em>
PV = nRT
V = nRT / P
<em>Where P is pressure = 1atm at STP</em>
<em>V is volume = Our incognite</em>
<em>n are moles of the gas = 1.50 moles</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K</em>
<em />
V = nRT / P
V = 1.50mol*0.082atmL/molK*273.15K / 1atm
V = 33.6L
<h3>C. 33.6L</h3>
