Answer:
aldehyde
carbon-1
ketone
carbon-2
Explanation:
Monosaccharides are colorless crystalline solids that are very soluble in water. Moat have a swwet taste. D-Fructose is the sweetest monosaccharide.
In the open chain form, monosaaccharides have a carbonuyl group in one of their chains. If the carbonyl group is in the form of an aldehyde group, the monosaccharide is an aldose; if the carbonyl group is in the form of a ketone group, the monosaccharide is known as a ketose. glucose is an aldose while fructose is a ketose.
In D-glucose, there is an aldehyde functional group, and the carbonyl group is at carbon-1 when looking at the Fischer projection.
In D-fructose, there is a ketone functional group, and the carbonyl group is at carbon-2 when looking at the Fischer projection.
Answer:
60g/mol
Explanation:
By using nucleon numbers given on the periodic table, the mass of 1 mole of each element is:
C= 12g
H= 1g
O= 16g
Since molar mass is the sum of the masses of each element present in the compound,
Molar Mass (Mr) = 12+3(1)+12+16(2)+1 = 60g/mol
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams
therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams
Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
Both noticed that different atoms gives different colours of light when they are exposed to flame.
Answer:
Explanation:
Hello!
In this case, since the undergoing chemical reaction is:
We first need to identify the limiting reactant given the masses of nitrogen and hydrogen:
It means that only 0.647 moles of ammonia are yielded, so the resulting enthalpy change is:
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