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goblinko [34]
2 years ago
8

Explain how knowledge of acids/bases and neutralization can apply to the treatment of soil acidification

Chemistry
1 answer:
sammy [17]2 years ago
6 0

Explanation:

If soil consists of more acidic nature then, it does not allow plant growth.

In that situation, treat the soil with (anti-acid which is nothing but) base.

When an acid reacts with a base, a neutralization reaction takes place and salt and water are formed in this reaction.

The equation is shown below:

acid+base-> salt +water

For example, if the soil has more sulphuric acid traces then, it should be treated with lime.

H_2SO_4(aq)+Ca(OH)_2(aq)->CaSO_4(aq)+2H_2O(l)

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Convert 380 mmHg to atm.
tankabanditka [31]

Answer:

50662.5

Explanation:

6 0
2 years ago
Wear _______________________ when handling batteries, because they can explode or leak.
Basile [38]

The answer is: b. Safety glasses and acid-resistant gloves.

Battery acid (sulfuric acid) has pH = 0.

Sulfuric acid (H₂SO₄) is a strong acid, it means that the solution of sufuric acid is more acidic (pH<7) than water (pH = 7).

Chemical dissociation of sulfuric acid in water:  

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).  

Sulfuric acid can come in contact with eyes and hands, so it is important to wear safety glasses and acid-resistant gloves.

4 0
3 years ago
What is chemical reaction?<br>​
Aliun [14]

Answer:

a process that involves rearrangement of the molecular or ionic structure of a substance, as distinct from a change in physical form or a nuclear reaction

3 0
2 years ago
Read 2 more answers
The male monster has an HH genotype, and the female has a hh genotype. Will the baby monsters have horns?
viva [34]

Answer:

like the others its C

Explanation:

the dad has horns but the mom does not so the babys could or they could not

8 0
2 years ago
Read 2 more answers
If anyone could please help me i'd greatly appreciate it! I have tried over and over again and can not figure this out.
Papessa [141]

Answer:

%Ionization = 1.63%

Explanation:

Hydrazine in aqueous media theoretically forms a difunctional hydroxyl system. However, for this problem assume only monofunctional ionization occurs. A second hydroxyl ionization would not likely occur as the formal cationic charge formed in the 1st ionization would inhibit a second ionization.

H₂NNH₂ + 2H₂O => HONHNHOH => HONHNH⁺ + OH⁻; Kb = 1.3 x 10⁻⁶

So, assuming all OH⁻ and HONHNH⁺ are delivered in the 1st ionization then a good estimate of the %ionization can be calculated.

               HONHNHOH => HONHNH⁺  +  OH⁻

C(i) =>              0.490M                  0M           0M

ΔC =>                  -x                         +x             +x

C(eq) =>         0.490 - x                    x               x

                      ≅0.490M* => *x is dropped as Conc H₂NNH₂/Kb > 100

Kb = [HONHNH⁺][OH⁻]/[HONHNHOH]

1.3 x 10⁻⁶ = x²/0.490

=> x = [OH⁻] = [HONHNH⁺] = √[(1.3 x 10⁻⁶)(0.490)] = 8 x 10⁻⁴

=> %Ionization = (x/0.490)100% = (8 x 10⁻⁴/0.490)100% = 1.63%

7 0
3 years ago
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