Question

A railroad flatcar is traveling to the right at a speed of 13.0 m/s relative to an observer standing on the ground. someone is riding a motor scooteron the flatcar. what is the velocity (magnitude and direction) of the scooter relative to the flatcar if the scooterâs velocity relative to the observer on the ground is

Answer 1

Given:

$v \frac{x}{y} \frac {t} {0} = 13 \frac{m} {s}$

$v \frac{0} {g} = 0 \frac{m} s}$

SOLUTION:

(a) 

$v \frac{s} {t} = ? for v \frac{s} {0} = +18 \frac{m} {s}$

$v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {T} = +18 \frac {m} {s} + (-13 \frac {m} {s} )$

$v \frac {s} {t} = +5 \frac {m} {s}$

(b) 

$v \frac {s} {t} = ? for \frac {s} {0} = -3.0 \frac {m} {s}$

$v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {t} = -3.0 \frac {m} {s} + (-13 \frac {m} {s} ) = -16 \frac {m} {s}$

(c)

$v \frac {s} {t} = ? for \frac {s} {0} = 0 \frac {m} {s}$

$v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {t} = 0 \frac {m} {s} + (-13 \frac {m} {s} ) = -13 \frac {m} {s}$