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Umnica [9.8K]
3 years ago
6

HEY CAN ANYONE PLS HELP ME OUT IN DIS PLS!

Physics
2 answers:
Leona [35]3 years ago
8 0

The significant figure rules for addition and subtraction basically has you add or subtract as normal, but the rounding is where the rule kicks in. Specifically you round based on the least accurate decimal portion (the term with the least number of digits to the right of the decimal point).

We do this because we want to make sure we don't involve digits we aren't 100% sure of their accuracy.

==========================================================

Part A

Add up the values like normal

32.567+135.0+1.4567 = 169.0237

Now we look at the decimal portions of each number. We look at the number of digits to the right of each decimal point.

32.567 has three such digits (5,6 and 7)

135.0 only has one digit (the 0)

1.4567 has four digits (4,5,6,7)

The least accurate is 135.0 since we only know this to the tenths place. So we'll be rounding the sum we got above (169.0237) to the nearest tenth

169.0237 rounds to 169.0

<h3>Answer before rounding = 169.0237</h3><h3>Answer after rounding = 169.0</h3>

==========================================================

Part B

Add like normal

246.24+238.278+98.3 = 582.818

Then round to one decimal place since this is the fewest number of digits after the decimal point (in the number 98.3)

582.818 rounds to 582.8

<h3>Answer before rounding = 582.818</h3><h3>Answer after rounding = 582.8</h3>

==========================================================

Part C

Subtraction is handled in a similar fashion

4.829-0.26 = 4.569

Which rounds to 4.57 since two digits is the smallest number of digits after the decimal point. Put another way, 0.26 is the least of the accurate measurements comparing 4.829 and 0.26; we always go with the least accurate or weakest link when it comes to rounding sig figs. If we went the other way around, then we could be introducing data that isn't really there.

<h3>Answer before rounding = 4.569</h3><h3>Answer after rounding = 4.57</h3>
ryzh [129]3 years ago
3 0

Answer:

A) 169.0167

Explanation:

ive done this before

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The body went 450 meters within 30 seconds of starting the movement. In what time did the first 50 meters go?
Andrew [12]

3.33 seconds.

<u>Explanation:</u>

We can find the speed of the body using the formula,

Speed = Distance traveled in meters /  time taken in seconds

= 450 m / 30 seconds

= 15 m/s

So per second the distance traveled by the body is 15 m.

So time needed to travel 50 m can be found as,

time = distance/speed

= 50 m / 15 m /s

= 3.33 s

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Khaled said the North star is special because it appears all over the world and its changes position.
saw5 [17]
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Energy is inversely proportional to the wavelength of a wave. Which would have the GREATEST energy? A wave with a
Ivan

Answer:

A 5

Explanation:

The wave with the least amount of wavelength will have the greatest amount of energy.

Wavelength and energy shares an inverse relationship;

       E  = h f  = \frac{hc}{wavelength}

From this equation, we see that the higher the energy of a wave, the lesser its wavelength.

  • Choice A from the options has the least wavelength.
  • Wavelength is the distance between two successive crests of a wave.

This is why we see that in the electromagnetic spectrum, radio waves have the least energy because they have the longest wavelength.

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3 years ago
A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The
Ber [7]

Answer:

1. v=14.2259\ m.s^{-1}

2. F_T=25.8924\ N

3. \lambda=29.6373\ m

Explanation:

Given:

  • mass of slinky, m=0.87\ kg
  • length of slinky, L=6.8\ m
  • amplitude of wave pulse, A=0.23\ m
  • time taken by the wave pulse to travel down the length, t=0.478\ s
  • frequency of wave pulse, f=0.48\ Hz=0.48\ s^{-1}

1.

\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel

v=\frac{6.8}{0.478}

v=14.2259\ m.s^{-1}

2.

<em>Now, we find the linear mass density of the slinky.</em>

\mu=\frac{m}{L}

\mu=\frac{0.87}{6.8}\ kg.m^{-1}

We have the relation involving the tension force as:

v=\sqrt{\frac{F_T}{\mu} }

14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }

202.3774=F_T\times \frac{6.8}{0.87}

F_T=25.8924\ N

3.

We have the relation for wavelength as:

\lambda=\frac{v}{f}

\lambda=\frac{14.2259}{0.48}

\lambda=29.6373\ m

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Answer:

47.46 kilometers an hour

Explanation:

hope this helped

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