Answer: 88 Earth days
Explanation:
According to the Kepler Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.
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In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit:
(1)
If we assume the orbit is circular and apply Newton's law of motion and the Universal Law of Gravity we have:
(2)
Where 
is the mass of the massive object and 
is the universal gravitation constant. If we assume constant and larger enough to consider really small, we can write a general form of this law:
(3)
Where is in units of Earth years, is in AU (<u>1 Astronomical Unit is the average distane between the Earth and the Sun)</u> and is the mass of the central object in units of the mass of the Sun.
This means when we are making calculations with planets in our solar system 
.
Hnece, in the case of Mercury:
(4)
Isolating :
(5)
(6)
This means the period of Mercury is 88 days.
Answer:
Force that acted on the body was F = 13 N
Explanation:
If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s
When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:
which in our case becomes;
and we can solve for the acceleration as:
a = 10/10 m/s^2 = 1 m/s^2
Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:
F = 13 kg * 1 m/s^2 = 13 N
Answer: It is the ratio of solute in a solution to either solvent or total solution.
Explanation:
I would think the answer would be c
