In simpler terms, a proton and neutron weigh 1 amu (atomic mass unit) each.
The nucleus has 15 protons and 18 neutrons. Since a proton's and a neutron's weight is only 1 amu, we can simply add the number of protons and neutrons to find the total mass of the nucleus:
The nucleus' mass is 33 amu.
Answer:
a) h / h₀ = 1,682
, b) h / h₀ = 1.11
, c) h / h₀ = 2.07
Explanation:
For this exercise let's look for the growth equation, as they indicate that it is exponential
h = h₀
The initial height is 9 ”, so the constant
h₀ = 9”
Let's use the given values
h = 15.1655”
t = 5 days
h / h₀ =
α = 1 / t ln h / h₀
α = 1/5 ln (15.1655 / 9)
α = 0.104
h = 9 e^{0.104 t}
a) the growth factor is the relationship between the initial value and the current value
h / h₀ =
h / h₀ = 1,682
b) for t = 1 day
h / h₀ =
h / h₀ = 1.11
c) for t = 7 days
h / h₀ = e^{0.104 7}
h / h₀ = 2.07
Answer:
F = 2.26 × 10⁻³ N
Explanation:
given,
length of rod = 11 cm
charge = 19 nC
linear charge density = 3.9 x 10⁻⁷ C/m
electric force at 2 cm away.
F = E q
integrating from 0.02 to 0.02 + L
F = 2.26 × 10⁻³ N