Which description of nitrogen-15 is correct?

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl

diamong [38]

Answer:

For A: The average molecular speed of Ne gas is 553 m/s at the same temperature.

For B: The rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

Explanation:

For A:

The average molecular speed of the gas is calculated by using the formula:

$V_{gas}=\sqrt{\frac{8RT}{\pi M}}$

OR

$V_{gas}\propto \sqrt{\frac{1}{M}}$

where, M is the molar mass of gas

Forming an equation for the two gases:

$\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}$ .....(1)

Given values:

$V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol$

Plugging values in equation 1:

$\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s$

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

For B:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

$Rate\propto \frac{1}{\sqrt{M}}$

Where, M is the molar mass of the gas

Forming an equation for the two gases:

$\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}$ .....(2)

Given values:

$Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol$

Plugging values in equation 2:

$\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr$

Hence, the rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

8 0

3 years ago

PLEASE NO FAKE ANSWERS!! Chemistry!!! Please will give brainliest !! Show work

Drupady [299]

When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

<h3>What is Limiting reagent ?</h3>

Limiting reagents are the substances that are completely consumed first in a chemical reaction.

Given ;

Amopunt of Zn : 1 mole
Amount of O₂ : 2 mole

Given equation ;

2Zn + O₂ --> 2ZnO

As according to given chemical equation,

2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.

Therefore,

1 mole of Zn will require 0.5 mole of O₂.

But,

the given amount of O₂ is 2 mole which is excess

Hence,

Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.

Therefore,

If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)

Thus,

1 mole of Zn will produce = 2/2 x 1

= 1 mole of ZnO

Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

Learn more about Limiting reagent here ;

brainly.com/question/11848702

#SPJ1

3 0

2 years ago

What is the rule of thumb for the activity trends of metals and nonmetals? Explain and give examples.

pentagon [3]

This for metal......the farther to the left the more reactive they are. Group 1 metals, which include sodium and potassium, are so highly reactive that they do not exist in nature by themselves

Thats non metals..........the farther to the right the more reactive they are *with the exception of group 18* which are the noble gases and do not react at all. The most reactive are group 17, which include fluorine and chlorine. These non-metals, like group 1, rarely exist by themselves because of their high reactivity.

5 0

4 years ago

When 5.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C, 169.5 kJ are

NNADVOKAT [17]

Answer:

∆E=155kJ

Explanation:

Check attachment

3 0

3 years ago

Why is the boiling of water a physical change if water changes from a liquid to a gas?

love history [14]

Answer:

because the water vapor still has the same molecular structure as liquid water (H2O). If the bubbles were caused by the decomposition of a molecule into a gas (such as H2O →H2 and O2), then boiling would be a chemical change.

Explanation:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water (H2O). If the bubbles were caused by the decomposition of a molecule into a gas (such as H2O →H2 and O2), then boiling would be a chemical change.

7 0

2 years ago