Gay-Lussac's law gives the relationship between pressure and temperature of a gas.
it states that for a fixed amount of gas of constant volume pressure is directly proportional to temperature.
P/T = k
where P - pressure, T - temperature and k - constant

where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
temperature should be in the kelvin scale,
T1 = 22 °C + 273 = 295 K
substituting the values in the equation

T = 492 K
new temperature - 492 - 273 = 219 °C
To answer this item, we solve first for the mass of the solution by multiplying the density by the volume. That is,
m = (density)(volume)
Substituting the known values,
m = (1.50 g/mL)(5L)(1000 mL/1L)
m = 7500 grams
To determine the mass of the salt in the solution, multiply the calculated mass of the solution by the decimal equivalent of the percent salt in the solution.
m of salt = (7500 g)(0.33)
m of salt = 2475 grams
<em>Answer: 2475 grams</em>
Answer is: mass of 1,58 mol of water is 28,44 grams.
n(H₂O) = 1,58 mol.
M(H₂O) = 2 · 2 g/mol + 16 g/mol.
M(H₂O) = 18 g/mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 1,58 mol · 18 g/mol.
m(H₂O) = 28,44 g.
n - amount of substance.
M - molar mass.
BE CAREFUL! If it is a controlled lab wear saftey equiptment. But it can blow up. So careful...