Moles of NH3 = mass of NH3/molecular mass of NH3 = 1.7/17= O.1 MOLES.
Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
Answer:
mole fraction benzene = 0.62
mole fraction toluene = 0.38
Explanation:
Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:
<h2>p total = x₁ P⁰₁ + x₂ P⁰₂</h2>
where x1 and x2 for this solution denote the mole fractions of benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.
Solving the algebraic equation:
75 x₁ + 22 x₂ = 55
75 x₁ + 22 ( 1- x₁) = 55 (since x₁ + x₂ = 1)
75 x₁ + 22 - 22 x₁ = 55
53 x₁ = 33
x₁ = 0.62
x₂ = 1 - 0.62 = 0.38
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