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3 years ago

Give the following for SO2 and BrF5:

Chemistry

1 answer:

frosja888 [35]3 years ago

6 0

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

Domain geometry is trigonal planar.

But there is a lone pair on the central atom.

So, according to VSEPR theory,

the molecular geometry becomes bent or V-shape.

Hybridization on the central atom is

$sp^{2}$ .

Consider the molecule BrF5:

The central atom is Br.

The number of domains on the central atom is six.

Domain geometry is octahedral.

But the central atom has a lone pair of electrons.

So, the molecular geometry becomes square pyramidal.

The hybridization of the central atom is $sp^{3} d^{2}$ .

The shapes of SO2 and BrF5 are shown below:

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= 3 × 10⁻³ mol

Beaker II:

Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.

H⁺][OH⁻] = 1 × 10⁻¹⁴ Divide each side by [H⁺]

[OH⁻] = (1 × 10⁻¹⁴)/[H⁺]

[OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)

[OH⁻] = 0.01 mol·L⁻¹

Moles of OH⁻ = 0.100 L × 0.01 mol/1 L

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B. Moles after mixing

H⁺ + OH⁻ ⟶ H₂O

I/mol: 3 × 10⁻³ 1 × 10⁻³

C/mol: -1 × 10⁻³ -1 × 10⁻³

E/mol: 2 × 10⁻³ 0

You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.

You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.

C. pH

[H⁺] = (2 × 10⁻³ mol)/(0.200 L)

= 1 × 10⁻² mol·L⁻¹

pH = -log[H⁺ ]

= -log(1 × 10⁻²)

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Answer:

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Explanation:

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