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2 years ago

use dimensional analysis to determine how many atoms of o2 produced in a reaction that yields 2 mol of o2

Chemistry

1 answer:

Alex73 [517]2 years ago

8 0

The number of atoms of oxygen is 2.4 * 10^24.

<h3>How many atoms are produced?</h3>

We know that mole of a substance contains the Avogadro's number of atoms. The Avogadro's number gives the number of atoms, molecules, ions and atoms that could be found in one mole of a substance.

Now;

Given that ;

1 mole of oxygen contains two atoms of oxygen, the number of atoms that are contained in 2 moles of the oxygen molecule is;

2 * 2 * 6.023 * 10^23

= 2.4 * 10^24

Learn more about dimensional analysis:brainly.com/question/13078117

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Object a has a mass of 12 G and a volume of 8 cm3 object be has a mass of 20 G and a volume of 8 cm3 which object has a greater

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Answer:

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Explanation:

Given data:

Mass of object A = 12 g

Volume of object A = 8 cm³

Mass of object B = 20 g

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Densities = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

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V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Density of object A:

d = m/v

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d = 1.5 g/cm³

Density of object B:

d = m/v

d = 20 g/ 8 cm³

d = 2.5 g/cm³

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A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use thi

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Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

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Formula:

Molarity = number of moles of solute / L of solution

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Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi

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Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

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Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

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There will react xM of COCl2

Since the mole ratio is 1:1

The final concentration of CO and Cl2 will be X M

The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc= [CO] *[Cl2] / [COCl2] = 8.33*10^-4

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8.33 * 10^-4 = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl2]

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To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

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