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xenn [34]
2 years ago
13

Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves _____ the nuc

leus and it takes _____ energy to remove it.
Chemistry
1 answer:
GarryVolchara [31]2 years ago
7 0

Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

Ionization energy, also known as ionization energy, would be the minimal amount of energy needed to free an isolated gaseous atom's or molecule's least loosely bonded electron.

First ionization energy often drops as you advance down a group on the periodic table. This occurs even though the outermost electron would be typically held less securely and can be removed with less energy since it travels farther away from the nucleus.

Therefore, Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

To know more about Ionization energy

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Answer:

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A sample of iron metal is placed in a graduated cylinder. it is noted that 10.4 ml of water is displaced by the iron. the iron i
Pavel [41]
<h3>Answer:</h3>

                 162.43 g of FeCl₂

<h3>Explanation:</h3>

Step 1: Calculate mass of Fe;

As,

                                   Density  =  Mass ÷ Volume

Or,

                                   Mass  =  Density × Volume

Where Volume is the volume of water displaced  =  10.4 mL

Putting values,

                                   Mass  =  7.86 g.mL⁻¹ × 10.4 mL

                                   Mass  =  81.744 g of Fe

Step 2: Calculate amount of FeCl₂;

The balance chemical equation is as follow,

                                Fe  +  2 HCl   →    FeCl₂  +  H₂ ↑

According to this equation,

       55.85 g (1 mol) Fe produced  =  110.98 g (1 mol) of FeCl₂

So,

               81.744 g Fe will produce  =  X g of FeCl₂

Solving for X,

                    X  =  (81.744 g × 110.98 g) ÷ 55.85 g

                     X =  162.43 g of FeCl₂

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3 years ago
In a solution of a carbonated beverage the water is what? Solute, saturated, solvent or precipitate
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Burning gasoline is an _____________ reaction.
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Answer:

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3 years ago
Read 2 more answers
When blood is donated, sodium oxalate solution is used to precipitate Ca2+, which triggers clotting. A 122.0−mL sample of blood
icang [17]

Answer:

[Ca2+] = 3.36 * 10^-8 M

Explanation:

Step 1: Data given

A 122.0−mL sample of blood contains 9.70 * 10^−5 g Ca2+/mL.

A technologist treats the sample with 100.0 mL of 0.1550 M Na2C2O4.

Ksp = 2.30 * 10^−9

Step 2: Calculate mass of Ca2+

Mass Ca2+ = 9.70 * 10^−5 g Ca2+/mL * 122 mL

Mass Ca2+ = 0.011834 grams

Step 3: Calculate moles of Ca2+

Moles Ca2+ = mass Ca2+ / molar mass Ca2+

Moles Ca2+ = 0.011834 grams / 40.078 g/mol

Moles Ca2+ = 2.95 *10^-4 moles = 0.000295

Step 4: Calculate moles of C2O4^2-

Moles C2O4^2- = Molarity * volume

Moles C2O4^2- = 0.1550 M * 0.100 L

Moles C2O4^2- = 0.0155 moles

Step 5: Calculate limiting reactant

Ca2+ is the limiting reactant. It will completely be consumed ( 0.000295 moles).

C2O4^2- is in excess. There will 0.000295 moles be consumed. There will remain 0.0155 - 0.000295 = 0.015205 moles of C2O4^2-

Step 6: Calculate total volume

Total volume = 122.0 mL + 100.0 mL = 222.0 mL = 0.222 L

Step 7: Calculate concentration CaC2O4

[CaC2O4] = 0.000295 mol / 0.222 L

[CaC2O4] = 0.00133 M

Step 8: Calculate concentration of C2O4^2-

[C2O4^2-] = 0.015205 mol / 0.222L

[C2O4^2-] = 0.0685 M

Step 9: Calculate [Ca2+]

Ksp = 2.3 * 10^-9 = [Ca2+] [C2O42-]

2.3 * 10^-9 = X * (X+0.0685)

X = [Ca2+] = 3.36 * 10^-8 M

6 0
3 years ago
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