C = n/V
n = C×V
n = 4,41M × 1,25L
n = 5,5125 mol
mKI: 39+127 = 166 g/mol
1 mol --------- 166g
5,5125 mol --- X
X = 166×5,5125 = 915,075g KI
:)
Answer:
The enthalpy change in the the reaction is -47.014 kJ/mol.
Explanation:

Volume of water in calorimeter = 22.0 mL
Density of water = 1.00 g/mL
Mass of the water in calorimeter = m

Mass of substance X = 2.50 g
Mass of the solution = M = 2.50 g + 22 g = 24.50 g
Heat released during the reaction be Q
Change in temperature =ΔT = 28.0°C - 14.0°C = 14.0°C
Specific heat of the solution is equal to that of water :
c = 4.18J/(g°C)


Heat released during the reaction is equal to the heat absorbed by the water or solution.
Heat released during the reaction =-1.433 kJ
Moles of substance X= 
The enthalpy change, ΔH, for this reaction per mole of X:

Answer:
NH3>H2O>Cl-
Explanation:
The given wavelengths of maximum absorption for each complex can be used to estimate the magnitude of field splitting of the respective ligands as shown in the image attached. The field splitting is reported in the unit kilojoule per mole (KJmol-1).
It can be seen from the calculation in the image attached that ammonia shows the highest crystal field splitting followed by water and lastly the chloride anion. This corresponds to the respective positions of these species in the spectrochemical series. Water and the chloride ion are weak field ligands.
Explanation:
2. 
First, we need to find the number of moles of
at 300K and 1.5 atm using the ideal gas law:


Now use the molar ratios to find the number of moles of ethane to produce this much
.


Finally, convert this amount to grams using its molar mass:


3. 
Convert 75 g Zn into moles:

Then use the molar ratios to find the amount of H2 produced.

Now use the ideal gas law
to find the volume of H2 produced at 23°C and 4 atm:


Answer:
2.25 M <========= I do not see this in your selection of answers !
Explanation:
Mole weight of Li F
( from periodic table ) = 6.94 + 18.998 = 25.938 gm/mole
56 gm / ( 25.938 gm /mole) = 2.15899 moles
2.15899 mole / (.959) L = 2.25 M