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densk [106]
4 years ago
10

Explain objects in space motion. How do they move? What affects their motion?

Physics
1 answer:
Verizon [17]4 years ago
5 0
Objects in space follow the laws or rules of physics, just like objects on Earth do. Things in space have inertia. That is, they travel in a straight line unless there is a force that makes them stop or change. The movement of things in space is influenced by gravity.
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a boy Held a book of weight 50 newton’s in his fully outstretched hand, at a distance of 50 cm away calculate the moment of forc
miss Akunina [59]

Answer:

the moment of force is 25 Nm.

Explanation:

Given;

weight of the book, F = 50 N

distance through which his hand was stretched, d = 50 cm = 0.5 m

The moment of force is calculated as;

moment of force = F x r

moment of force = 50 N x 0.5 m

moment of force = 25 Nm

Therefore, the moment of force is 25 Nm.

7 0
3 years ago
Good afternoon.....from bangladesh....
Step2247 [10]

Answer:

good afternoon

Explanation:

4 0
3 years ago
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There was a major collision of an asteroid with the Moon in medieval times. It was described by monks at Canterbury Cathedral in
LekaFEV [45]

Answer:

c = 3.00E108 m/s = 3.00E5 km/s

t = S / v = 3.84E5 / 3.00E5 = 1.28 sec

4 0
3 years ago
What is the wavelength of a radiowave that has a frequency of 9.650 x10^7 Hz (cycles per second)?h = 6.6261 x10^-34 J/sc = 2.998
slava [35]

Hello!!

For this, we only need frequency and speed, so for calculate we applicate formula:

\boxed{\lambda = V/f}

\textbf{Being:}

\sqrt{} \lambda = Wavelength = \   ?

\sqrt{} V = Velocity = 2.998*10^{8} \ m/s

\sqrt{} f = Frequency = 9,650*10^{7} \ Hz

\text{Then let's \textbf{replace it according} we information:}

\lambda = 2,998*10^{8} \ m /s  / 9,650*10^{7} \ Hz

\lambda  =  3.106 \ m

\textbf{Result:}\\\text{The wavelength of the radiowave is \textbf{3.106 meters}}

4 0
3 years ago
What would be the resonant frequency for a series RLC circuit with the following components: a 1,000 Ω resistor, a 900 mH induc
lesya [120]

Answer:

<em>The resonance frequency = 0.978 Hz</em>

Explanation:

Resonance: This is a point in an A.c circuit where the capacitive reactance is equal to the inductive reactance. The frequency at resonance is called<em> Resonance Frequency. Mathematically, </em><em>resonance frequency is expressed as</em>

f₀ = 1/2π√(LC)......................................... Equation 1

Where f₀ = resonance frequency, L = inductance of the inductor, C = capacitance

<em>Given: L = 900 mH = (900/1000) H = 0.9 H, C = 0.014 mF = (0.014/1000) F = 0.000014 F</em>

<em>Constant: π = 3.143</em>

Substituting these values into equation 1

f₀ = 1/2×3.143√(0.9×0.000014)

f₀ = 1/6.286√(0.0000126)

f₀ = 1/6.286×0.00355

f₀ = 1/0.0223

f₀ = 0.978 Hz.

<em>Therefore the resonance frequency = 0.978 Hz</em>

4 0
3 years ago
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