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alina1380 [7]
3 years ago
14

a boy Held a book of weight 50 newton’s in his fully outstretched hand, at a distance of 50 cm away calculate the moment of forc

e
Physics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

the moment of force is 25 Nm.

Explanation:

Given;

weight of the book, F = 50 N

distance through which his hand was stretched, d = 50 cm = 0.5 m

The moment of force is calculated as;

moment of force = F x r

moment of force = 50 N x 0.5 m

moment of force = 25 Nm

Therefore, the moment of force is 25 Nm.

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Which of the following is an example of the law of conversion of energy
ruslelena [56]
Is there a picture so I can help you
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A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 22.0 m/s and returns the shot with the ball
morpeh [17]
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What is the acceleration of an object that starts at rest and reaches 100 m/s in 4 seconds
azamat

Answer:

<h3>The answer is 25 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}

where

v is the velocity

t is the time

From the question

v = 100 m/s

t = 4 s

We have

a =  \frac{100}{4}  \\

We have the final answer as

<h3>25 m/s²</h3>

Hope this helps you

7 0
4 years ago
A uranium-238 atom can break up into a thorium-234 atom and a particle called an alpha particle, αα-4. The numbers indicate the
alexdok [17]

Answer: E = 5.80*10^-13 J

Explanation:

Given

We use the law of conservation of momentum to solve this

Momentum before breakup = momentum after breakup

0 = m1v1 + m2v2

0 = 238m * -2.2*10^5 + 4m * v2

0 = -523.6m m/s + 4m * v2

v2 * 4m = 523.6m m/s

v2 = 523.6 m m/s / 4m

v2 = 130.9*10^5 m/s

v2 = 1.31*10^7 m/s

Using this speed in the energy equation, we have

E = 1/2m1v1² + 1/2m2v2²

E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²

E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]

E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)

E = 9.56*10^-15 + 5.7*10^-13

E = 5.80*10^-13 J

3 0
3 years ago
Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app
Aleks04 [339]

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

θ = 30°

Learn more about the banking angle:brainly.com/question/26759099?r

#SPJ1

8 0
2 years ago
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