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3 years ago

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A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire ful

ly lies in a magnetic field given by (0.3y)i + (0.4y)j Tesla. The magnetic force on the wire is *

1 answer:

il63 [147K]3 years ago

8 0

Answer:

1.875*10^-5

Explanation:

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3 years ago

If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in

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To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

$F_{initial} = \frac{kq_1q_2}{r^2}$

Here,

k = Coulomb's constant

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r = Distance between them

As the distance is doubled so,

$F_{final} = \frac{kq_1q_2}{( 2r )^2}$

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$F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}$

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Answer:

The correct option is a

Explanation:

From the question we are told that

The mass of the block is $m = 4.84 \ kg$

The height of the vertical drop is $h = 19.6 \ m$

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