Answer:
I'm glad you asked!
Step-by-step explanation:
OK,let's simplify the number for a equivalent expression.
Distribute:
Combine Like Terms:
The Final Answer is : 
Answer:
this isnt a math question
Step-by-step explanation:
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In probability, there are hint clues that you must be vigilant of. When it tells you to find the probability of event 1 'or' event 2, you must ADD their individual probabilities. When it tells you to find the probability of event 1 'and' event 2, you must MULTIPLY their individual probabilities.
Now, you have two dices. You are asked to find the probability of getting a face of 3, 4 or 5. The probability of each face of a dice is 1/6, because there are a total of 6 faces. When you use two dices, it becomes 2/12 or still 1/6. So, the total probability of getting either 3, 4 or 5 is: 1/6 + 1/6 + 1/6 = 1/2. However, you still have to multiply this with the total probability of getting a prime numbers which are 1, 2, 3 and 5. Thus, 1/6 + 1/6 + 1/6 + 1/6 = 2/3
Hence, the total probability would be 1/2 * 2/3 = 1/3 or 33%
Hi so u would multiply then add 2 to get ur answer
a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,
6! = 6 
5
= 30 4
= 360 2 = 720 possible ways to order 6 people in a row
b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.
5! = 5 4
= 20 3
= 120 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.
In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )
c. With each husband on the left, there are 3 people left, all women, that we have to consider here.
3! = 3 2 6 ways to arrange 3 couples in a row, the husband always to the left
