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I am Lyosha [343]
3 years ago
13

Which is generally stronger, intermolecular interactions or intramolecular interactions? Which is generally stronger, intermolec

ular interactions or intramolecular interactions? Intermolecular interactions are generally stronger. Intramolecular interactions are generally stronger. These interactions are equally strong.
Part B Which of these kinds of interactions are broken when a liquid is converted to a gas? Which of these kinds of interactions are broken when a liquid is converted to a gas?

a. Only intermolecular interactions are broken when a liquid is converted to a gas.
b. Only intramolecular interactions are broken when a liquid is converted to a gas.
c. Both of these interactions are broken.
Chemistry
1 answer:
Inessa [10]3 years ago
7 0

Answer:

A. Intramolecular interactions are generally stronger.

B. a. Only intermolecular interactions are broken when a liquid is converted to a gas.

Explanation:

<em>A. Which is generally stronger, intermolecular interactions or intramolecular interactions?</em>

Intramolecular interactions, in which electrons are gained, lost or shared, constitute true bonds and are one or two orders of magnitude stronger than intermolecular interactions.

<em>B. Which of these kinds of interactions are broken when a liquid is converted to a gas?</em>

When a liquid vaporizes, the intermolecular attractions are broken, that is, molecules get more separated. However, true bonds are not broken which is why the molecules keep their chemical identity.

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3 0
2 years ago
Iron fluoride (FeF2) dissociates according to the following equation:
melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

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FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0
3 years ago
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