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Anna007 [38]
3 years ago
10

Which method reduces carbon dioxide emissions by storing carbon dioxide for a long time?

Chemistry
2 answers:
Rudiy273 years ago
5 0

B. carbon sequestration

Explanation:

Carbon sequestration is a method that reduces carbon dioxide emissions by storing them for a long time.

  • It is long term harvesting or sequestering of carbon dioxide from the atmosphere in order to avert air pollution and climatic change problems.
  • Carbon sequestration is usually employed in the storage and capture of atmospheric carbon dioxide.
  • The carbon dioxide can be sequestered using biologic or geologic means.
  • Carbon dioxide gas is used to enhance oil recovery from geologic formations that have low permeability or those with low formation pressure to push out the oil.

Learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

aliina [53]3 years ago
5 0

Answer:

B. Carbon sequestration

Explanation:

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Look at the two thermometers.
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Thermometer A, because it measures accurately to the tenths digit.

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An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

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3 years ago
What biological molecules transport other substances, provide structural
PSYCHO15rus [73]

The biological molecules that transport other substances are the proteins.

<h3>What are proteins?</h3>

Proteins are biological macromolecules that contains nitrogen in their molecules and are the building block of a living organism.

The proteins perform the following functions:

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