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Anna007 [38]
3 years ago
10

Which method reduces carbon dioxide emissions by storing carbon dioxide for a long time?

Chemistry
2 answers:
Rudiy273 years ago
5 0

B. carbon sequestration

Explanation:

Carbon sequestration is a method that reduces carbon dioxide emissions by storing them for a long time.

  • It is long term harvesting or sequestering of carbon dioxide from the atmosphere in order to avert air pollution and climatic change problems.
  • Carbon sequestration is usually employed in the storage and capture of atmospheric carbon dioxide.
  • The carbon dioxide can be sequestered using biologic or geologic means.
  • Carbon dioxide gas is used to enhance oil recovery from geologic formations that have low permeability or those with low formation pressure to push out the oil.

Learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

aliina [53]3 years ago
5 0

Answer:

B. Carbon sequestration

Explanation:

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An unidentified compound contains only phosphorous and fluorine, meaning we could write its formula as PxFy. Heating 0.2324 g of
cricket20 [7]

Answer:

The molecular formula of the compound is P2F4

Explanation:

Step 1: Data given

Mass of the compound  = 0.2324 grams

Volume of container = 378 mL

Pressure at 77 °C = 97.3 torr

The gaseous PxFy was then reacted with an aqueous solution of calcium chloride, and all of the fluorine was converted to 0.2631 g of CaF2.

Molar mass CaF2 = 78.07 g/mol

Step 2: Calculate moles CaF2

Moles CaF2 = 0.2631 g/ 78.07 g/mol=0.003370

Step 3: Calculate moles F

For every 1 mol CaF2 we have 1 mol Ca2+ and 2 moles F-

moles F- = 2 * 0.003370=0.006740

Step 4: Calculate mass of F

mass F =  0.006740 mol * 19.00 g/mol=0.1281 g

Step 5: Calculate mass of P

mass P = mass of compound - mass of F = 0.2324 - 0.1281 =0.1043 g

Step 6: Calculate moles P

moles P = 0.1043 g/ 30.97 g/mol=0.003368 moles

Step 7: Calculate mol ratio

We divide by the smallest amount of moles

P: 0.003368/0.003368 =1

F: 0.006740/ 0.003368 =2

The empirical formula is PF2

The empirical formula has a molar mass of 68.97 g/mol

Step 8: Calculate moles of compound

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with p = the pressure of the gas = 97.3 torr = 97.3/760 = 0.128 atm

⇒ with V = the volume of the gas = 0.378 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 77.0 °C = 350 Kelvin

Number of moles =(0.128 *0.378)/(0.08206*350)

Number of moles =

moles gas = pV/RT = 0.128 atm x 0.378 dm^3/ 0.08206x350 K=0.00168  

Step 9: Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.2324 grams / 0.00168 moles

Molar mass = 138 g/mol

Step 10: Calculate the molecular formula

138.0 / 68.97 = 2

2*(PF2) = P2F4

The molecular formula of the compound is P2F4

4 0
3 years ago
For each of the following ionic bonding examples, show the transfer of electrons, the ions resulting with the charges and the fi
fgiga [73]

Answer:

BaO

  • Ba gives up two electrons and becomes Ba⁺²
  • O takes two electron and becomes O⁻²

Al₂O₃

Mg₃P₂

Na₂O

CaCl₂

6 0
3 years ago
. A base increases the OH- ion concentration of water.. True. False
HACTEHA [7]
It is a completely true statement that a <span>base increases the OH- ion concentration of water. The correct option among the two options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
8 0
3 years ago
Read 2 more answers
What is the maximum mass of b4c that can be formed from 2.00 moles of boron(iii) oxide?
anzhelika [568]

The maximum mass of B₄C that can be formed from 2.00 moles of boron (III) oxide is 55.25 grams.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.

Given chemical reaction is:

2B₂O₃ + 7C → B₄C + 6CO

From the stoichiometry of the reaction, it is clear that:

2 moles of B₂O₃ = produces 1 mole of B₄C

Now mass of B₄C will be calculated by using the below equation:

W = (n)(M), where

  • n = moles = 1 mole
  • M = molar mass = 55.25 g/mole

W = (1)(55.25) = 55.25 g

Hence required mass of B₄C is 55.25 grams.

To know more about stoichiometry, visit the below link:

brainly.com/question/25829169

#SPJ1

3 0
3 years ago
What is the temperature in kelvins of -14°C?
julia-pushkina [17]
Answer choice B 259 kelvins
3 0
2 years ago
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